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2 years ago

Calculate the current flowing if a charge of 36 kilocoulombs flows in 1 hour.

Physics

1 answer:

o-na [289]2 years ago

6 0

Answer:

Current = 10 Amperes.

Explanation:

Given the following dat;

Quantity of charge, Q = 36 kilocoulombs (KC) = 36 * 1000 = 36000C

Time = 1 hour to seconds = 60*60 = 3600 seconds

To find the current;

Quantity of charge = current * time

Substituting in the equation

36000 = current * 3600

Current = 36000/3600

Current = 10 Amperes.

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Why does laser beam might appear blue and another laser beam might appear red?

Alenkasestr [34]

The red laser will have a hotter temperature than the blue, so it is red because it is hot
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4 0

3 years ago

Read 2 more answers

If a 25 kg lawnmower produces 347 w and does 9514 J of work, for

Igoryamba

Steps 1 and 2)

The variables are W = work, P = power, and t = time. In this case, W = 9514 joules and P = 347 watts.

The goal is to solve for the unknown time t.

-----------------------

Step 3)

Since we want to solve for the time, and we have known W and P values, we use the equation t = W/P

-----------------------

Step 4)

t = W/P

t = 9514/347

t = 27.4178674351586

t = 27.4 seconds

-----------------------

Step 5)

The lawn mower ran for about 27.4 seconds. I rounded to three sig figs because this was the lower amount of sig figs when comparing 9514 and 347.

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Note: we don't use the mass at all

6 0

3 years ago

Suppose that the acceleration of a model rocket is proportional to the difference between 160 ft/sec and the rocket's velocity.

Levart [38]

Answer:

Explanation:

Given ,

dv / dt = k ( 160 - v )

dv / ( 160 - v ) = kdt

ln ( 160 - v ) = kt + c , where c is a constant

when t = 0 , v = 0

Putting the values , we have

c = ln 160

ln ( 160 - v ) = kt + ln 160

ln ( 160 - v / 160 ) = kt

(160 - v ) / 160 = $e^{kt}$

1 - v / 160 = $e^{kt }$

v / 160 = 1 - $e^{kt }$

v = 160 ( 1 - $e^{kt }$ )

differentiating ,

dv / dt = - 160k $e^{kt }$

acceleration a = - 160k $e^{kt }$

given when t = 0 , a = 280

280 = - 160 k

k = - 175

a = - 160 x - 175 $e^{kt}$

a = 28000 $e^{kt}$

when a = 128 t = ?

128 = 28000 $e^{kt}$

$e^{kt }$ = .00457

5 0

2 years ago

Convierta 164 decimetros a hectometros

-BARSIC- [3]

Answer:

sinco

Explanation:

6 0

3 years ago

A gas in a sealed container has a pressure of 50 kPa at 27°C. What will the pressure of the gas be if the temperature rises to 8

alexgriva [62]

Answer:

the final pressure of the gas is 60 kPa.

Explanation:

Given;

initial pressure of the gas, P₁ = 50 kPa = 50,000 Pa

initial temperature of the gas, T₁ = 27⁰ C = 27 + 273 = 300 k

final temperature of the gas, T₂ = 87⁰ C = 87 + 273 = 360 K

Let the final pressure of the gas = P₂

Apply pressure law;

$\frac{P_1}{T_1} = \frac{P_2}{T_2} \\\\P_2 = \frac{P_1T_2}{T_1} = \frac{50,000 \times 360}{300} = 60,000 \ Pa = 60 \ kPa$

Therefore, the final pressure of the gas is 60 kPa.

4 0

3 years ago