Maybe push or pull an object with a large amount of mass? you are force a (pushing through object) aka making contact. i hope i helped not good with physics :)
To solve this problem it is necessary to apply the concepts related to frequency as a function of speed and wavelength as well as the kinematic equations of simple harmonic motion
From the definition we know that the frequency can be expressed as
![f = \frac{v}{\lambda}](https://tex.z-dn.net/?f=f%20%3D%20%5Cfrac%7Bv%7D%7B%5Clambda%7D)
Where,
![v = Velocity \rightarrow 20m/s](https://tex.z-dn.net/?f=v%20%3D%20Velocity%20%5Crightarrow%2020m%2Fs)
![\lambda = Wavelength \rightarrow 35*10^{-2}m](https://tex.z-dn.net/?f=%5Clambda%20%3D%20Wavelength%20%5Crightarrow%2035%2A10%5E%7B-2%7Dm)
Therefore the frequency would be given as
![f = \frac{20}{35*10^{-2}}](https://tex.z-dn.net/?f=f%20%3D%20%5Cfrac%7B20%7D%7B35%2A10%5E%7B-2%7D%7D)
![f = 57.14Hz](https://tex.z-dn.net/?f=f%20%3D%2057.14Hz)
The frequency is directly proportional to the angular velocity therefore
![\omega = 2\pi f](https://tex.z-dn.net/?f=%5Comega%20%3D%202%5Cpi%20f)
![\omega = 2\pi *57.14](https://tex.z-dn.net/?f=%5Comega%20%3D%202%5Cpi%20%2A57.14)
![\omega = 359.03rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D%20359.03rad%2Fs)
Now the maximum speed from the simple harmonic movement is given by
![V_{max} = A\omega](https://tex.z-dn.net/?f=V_%7Bmax%7D%20%3D%20A%5Comega)
Where
A = Amplitude
Then replacing,
![V_{max} = (1*10^{-2})(359.03)](https://tex.z-dn.net/?f=V_%7Bmax%7D%20%3D%20%281%2A10%5E%7B-2%7D%29%28359.03%29)
![V_{max} = 3.59m/s](https://tex.z-dn.net/?f=V_%7Bmax%7D%20%3D%203.59m%2Fs)
Therefore the maximum speed of a point on the string is 3.59m/s
Continue on the momentum it has. The probe will continue in the same direction it is moving because there are no forces to act against it. I think this is the answer you are looking for...?
Answer:
B. Marginal cost equals long-run average total cost.
Explanation:
The zero profit condition implies that entry continues until all firms are producing at minimum long run average total cost. Since the marginal cost curve cuts the long run average total cost curve at its minimum point, marginal cost and long run average total cost must be equal in long run equilibrium.
Given the temperature, we can tell if the substance is cold or not relative to the reference temperature. For example, compared to the substance having a temperature of 15 degrees C, the substance is colder and it is hotter from the substance of temperature lesser than 12 degrees C.