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3 years ago

Calculate the heat energy released when 17.7 g of liquid mercury at 25.00 °c is converted to solid mercury at its melting point.

Physics

1 answer:

maria [59]3 years ago

8 0

Answer;

Q = 359.2-J

Explanation;

Given that;

Constants for mercury at 1 atm

Heat capacity of Hg(l) is 28.0 J/(mol*K)

melting point is 234.32 K

Enthalpy of fusion is 2.29 kJ/mol

17.7-g Hg / 200.6g/mol = 0.0882 mol Hg;

°C + 273 = 298 K;

2.29-kJ/mol = 2290-J/mol

Q = (m x ΔT x Cp) + (m x Hf)

Q = 0.0882-mol x (298 - 234.32) x 28.0-J/mol*K) + (0.0882-mol x 2290-J/mol)

Q = 157.26-J + 201.978-J

Q = 359.2-J

Q=359-J (3 sig fig allowed due to 17.7-g given in problem)

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