Question

A girl, standing on a bridge, throws a stone vertically downward with an initial velocity of 12.0 m/s, into the river below. if the stone hits the water 2.50 seconds later, what is the height of the bridge above the water?

Answer 1

Answer:

60.7 m high

Explanation:

d = v t   +  1/2 a t^2

  = 12 (2.5) + 1/2 (9.81)(2.5^2)  = 60.7  m