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hammer [34]
1 year ago
7

A girl, standing on a bridge, throws a stone vertically downward with an initial velocity of 12.0 m/s, into the river below. if

the stone hits the water 2.50 seconds later, what is the height of the bridge above the water?
Physics
1 answer:
erica [24]1 year ago
3 0

Answer:

60.7 m high

Explanation:

d = v t   +  1/2 a t^2

  = 12 (2.5) + 1/2 (9.81)(2.5^2)  = 60.7  m

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Answer:

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Explanation:

From the question given above, the following data were obtained:

Mass (m) of car = 600 Kg

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1. Determination of the original kinetic energy.

Mass (m) of car = 600 Kg

Initial velocity (v₁) of car = 0 m/s

Original kinetic energy (KE₁) =?

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KE₁ = ½ × 600 × 0²

KE₁ = 0 J

Thus, the original kinetic energy of the car is 0 J.

2. Determination of the final kinetic energy.

Mass (m) of car = 600 Kg

Final velocity (v₂) of car = 5 m/s

Final kinetic energy (KE₂) =?

KE₂ = ½mv₂²

KE₂ = ½ × 600 × 5²

KE₂ = 300 × 25

KE₂ = 7500 J

Thus, the final kinetic energy of the car is 7500 J

3. Determination of the work used.

Original kinetic energy (KE₁) = 0

Final kinetic energy (KE₂) = 7500 J

Work used =?

Work used = KE₂ – KE₁

Work used = 7500 – 0

Work used = 7500 J

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