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3 years ago

Which of the following describes the mesophyll in a leaf?

2 answers:

3 0

Mesophyll only occurs in some plants, and not the usual C3 plants that everyone learns about. In fact, mesophyll is mainly used in photosynthesis - for its light dependent reactions (primary reactions). Therefore, I'd say it's c) the structure which stores glucose for later use.

kotegsom [21]3 years ago

3 0

Answer:

A: the portion in which chlorophyll is found

Explanation:

edge 2020

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What are atoms and elements?

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Answer:

Atom, smallest unit into which matter can be divided without the release of electrically charged particles.

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3 years ago

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What happens if the Live wire and the Earth wire connections are swapped?

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A ball rolling down a hill for 9 seconds accelerates from 3 m/s to 34.5 m/s. What is the ball's rate of acceleration?

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3 years ago

What is the upper block's acceleration if the coefficient of kinetic friction between the block and the table is 0.13?

IgorLugansk [536]

Let us assume that pulley is mass less.

Let the tension produced at both ends of the pulley is T.

We are asked to calculate the acceleration of the block.

Let the masses of two bodies are denoted as $m_{1} \ and\ m_{2}\ respectively$

$Let\ m_{1} =1 kg\ and\ m_{2} =2 kg$

As per this diagram, the body having mass 1 kg is moving downward and the body having mass 2 kg is moving on the surface of the table.

Let the acceleration of each block is a .

For body having mass 1 kg:

The net force acting on 1 kg body will be-

$m_{1} g-T=m_{1} a$ [1]

Here tension in the rope will be vertically upward and weight of the body will be in vertical downward direction.

For body having mass 2 kg:

The coefficient of kinetic friction $[\mu]=0.13$

$Hence\ the\ frictional\ force\ F=\mu N$

$F=\mu m_{2} g$

Hence the net force acting on the body having mass 2 kg-

$T-\mu m_{2} g=m_{2} a$ [2]

Here the tension of the rope is towards right i.e along the direction of motion of the 2 kg block and frictional force is towards left.

Combining 1 and 2 we get-

$m_{1} g-T=m_{1}a$ [1]

$T-\mu m_{2}g= m_{2} a$ [2]

---------------------------------------------------

$[m_{1} -\mu m_{2} ]g=[m_{1} +m_{2} ]a$

$a=\frac{m_{1}-\mu m_{2}} {m_{1}+ m_{2}}*g$

$a=\frac{1-[2*0.13]}{1+2} *9.8\ m/s^2$

$a=\frac{0.74}{3} *9.8\ m/s^2$

$a=2.417 m/s$ [ans]

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3 years ago

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What characteristics of life can you identify in this figure?

kodGreya [7K]

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