Well, it's 40/4 for one minute, or 10 for one minute. You want 36 mins, so you multiply by the square root (6), to get $60, to which you also add the $90 for the lesson (result is $150)
Answer:
Side AB has a length of 4, and side BC has a length of 11.7
Based on the weight and the model that is given, it should be noted that W(t) in radians will be W(t) = 0.9cos(2πt/366) + 8.2.
<h3>
How to calculate the radian.</h3>
From the information, W(t) = a cos(bt) + d. Firstly, calculate the phase shift, b. At t= 0, the dog is at maximum weight, so the cosine function is also at a maximum. The cosine function is not shifted, so b = 1.
Then calculate d. The dog's average weight is 8.2 kg, so the mid-line d = 8.2. W(t) = a cos t + 8.2. Then calculate a, the dog's maximum weight is 9.1 kg. The deviation from the average is 9.1 kg - 8.2 kg = 0.9 kg. W(t) = 0.9cost + 8.2
Lastly, calculate t. The period p = 2π/b = 2π/1 = 2π. The conversion factor is 1 da =2π/365 rad. Therefore, the function with t in radians is W(t) = 0.9cos(2πt/365) + 8.2.
Learn more about radians on:
brainly.com/question/12939121
Answer: 95
Step-by-step explanation:
That’s the same as 0.95 of 100. That’s because 0.95 represents 0.95 and 100 represents 100, the of is the same as x. You can switch the two numbers and you can still get the same answer. So, 0.95 of 100 is 95.
according to the question
3x-1=0
3x=1
x=⅓
so
f(x)=18x³+x-1
f(⅓)=18.(⅓)³+⅓-1
f(⅓)=18.⅓.⅓.⅓+⅓-1
f(⅓)=6.⅑+⅓-1
f(⅓)=⅔+½-1
f(⅓)=0
<h3>therefore</h3><h3> the remainder is 0</h3>