One of the results is that the moon is near the earth and the other one, the oceans tide. Even though the earth can hold any object within
ts proximity, the ocean is partly attracted due to its liquid property. At night, the ocean tends to be attracted to the moon by creating a bulge and assigning it as ‘high tide’. This is due to the strong gravitational pull of th moon to the earth.
I hope this helps!
This might be right..
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Answer:</h3>
82.11%
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Explanation:</h3>
We are given;
- Theoretical mass of the product is 137.5 g
- Actual mass of the product is 112.9 g
We are supposed to calculate the percentage yield
- We need to know how percentage yield is calculated;
- To calculate the percentage yield we get the ratio of the actual mass to theoretical mass and express it as a percentage.
Thus;
% yield = (Actual mass ÷ Experimental mass) × 100%
= (112.9 g ÷ 137.5 g) × 100%
= 82.11%
Therefore, the percentage yield of the product is 82.11 %
Answer: The ratio of carbon to bromine atoms in the molecule is 3:1
Explanation:
Compound is a pure substance which is made from atoms of different elements combined together in a fixed ratio by mass. It can be decomposed into simpler constituents using chemical reactions.
Chemical formula shows the elements in a compound and the relative proportions of those elements.
The chemical formula given for the compound is
which means the ratio of carbon to bromine atoms is 3: 1.
Thus the ratio of carbon to bromine atoms in the molecule is 3:1
Answer:

Explanation:
Given that,
The distance between the centers of the two oxygen atoms in an oxygen molecule is
.
We need to convert this distance in inches.
We know that,
1 cm = 0.393 inches
We can solve it as follows :

So, the distance between the centers of the two oxygen atoms is
.
Answer:
Q = 233.42 J
Explanation:
Given data:
Mass of lead = 175 g
Initial temperature = 125.0°C
Final temperature = 22.0°C
Specific heat capacity of lead = 0.01295 J/g.°C
Heat absorbed by water = ?
Solution:
Heat absorbed by water is actually the heat lost by the metal.
Thus, we will calculate the heat lost by metal.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 22.0°C - 125.0°C
ΔT = -103°C
Q = 175 g × 0.01295 J/g.°C×-103°C
Q = -233.42 J
Heat absorbed by the water is 233.42 J.