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Kay [80]
3 years ago
8

What is the mass, in grams, of 28.74 mL of acetone?

Chemistry
2 answers:
a_sh-v [17]3 years ago
5 0
The question is asking to calculate the mass in grams of the acetone that has a volume of 28.74 ml. Base on that, the possible answer would be 22.58 grams. I hope you are satisfied with my answer and feel free to ask for more if you have questions and further clarifications  
slega [8]3 years ago
3 0

Answer:

22.73 g

Explanation:

To answer this question we need to look up the density of acetone in literature: 0.791 g/mL at 25 °C.

Using the density, we can calculate the mass of acetone in any given volume:

Density=\frac{mass}{volume}

0.791g/mL=\frac{mass}{28.74mL} \\mass=22.73g

So at 25 °C, 28.74 mL of acetone would weigh 22.73 g.

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For the reaction 2kclo3(s)→2kcl(s)+3o2(g) calculate how many grams of oxygen form when each quantity of reactant completely reac
barxatty [35]
First, we need to get the molar mass of:

KClO3 = 39.1 + 35.5 + 3*16 = 122.6 g/mol

KCl =39.1 + 35.5 = 74.6 g/mol

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From the given equation we can see that:

every 2 moles of KClO3 gives 3 moles of O2

when mass = moles * molar mass

∴ the mass of KClO3 = (2mol of KClO3*122.6g/mol) = 245.2 g

and the mass of O2 then = 3 mol * 32g/mol = 96 g

so, 245.2 g of KClO3 gives 96 g of O2

A) 2.72 g of KClO3: 

when 245.2 KClO3 gives → 96 g  O2

   2.72 g KClO3 gives →  X

X = 2.72 g KClO3 * 96 g O2/245.2 KClO3

    = 1.06 g of O2

B) 0.361 g KClO3:

when 245.2 g KClO3 gives → 96 g O2

     0.361 g KClO3 gives → X

∴ X = 0.361g KClO3 * 96 g / 245.2 g

       = 0.141 g of O2

C) 83.6 Kg KClO3:

when 245.2 g KClO3 gives → 96 g O2

       83.6 Kg KClO3 gives  →  X

∴X = 83.6 Kg* 96 g O2 /245.2 g KClO3

     = 32.7 Kg of O2

D) 22.4 mg of KClO3:

when 245.2 g KClO3 gives → 96 g O2

        22.4 mg KClO3 gives → X

∴X = 22.4 mg * 96 g O2 / 245.2 g KClO3

      = 8.8 mg of O2

     

 


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