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Irina-Kira [14]
3 years ago
5

If 75.0 of the isotopes of an element have a mass of 39.0 and 25.0% of the isotopes have a mass of 36.0 amu, what is the atomic

mass of the element?
Chemistry
1 answer:
pentagon [3]3 years ago
3 0

Answer:

Atomic mass of element = 38.25 amu

Explanation:

Let X-39 abundance = 75% and X-36 abundance = 25%

Atomic Mass of element = ∑ wt average contributions of each isotope ...

Wt Avg Contribution = fractional abundance x isotopic mass.    

Isotope      Isotopic Mass (amu)     Fractional Abundance     Wt Avg Contbn

 X-39                   39.00                           0.75                              29.25 amu

 X-36                   36.00                           0.25                                9.00 amu

∑ Wt Avg Contributions = 29.25 amu + 9.00 amu = 38.25 amu

=> Atomic mass of element = 38.25 amu

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malfutka [58]

Answer:

0.68 V

Explanation:

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3Mg(s) ---->3Mg^2+(aq) + 6e

For cathode;

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Overall balanced reaction equation;

3Mg(s) + 2Al^3+(aq) ----> 3Mg^2+(aq) + 2Al(s)

Since

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E°cathode = -1.676 V

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4 0
2 years ago
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Fiesta28 [93]

Answer:

m_{H_2SO_4}=81.7gH_2SO_4

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Explanation:

Hello,

Based on the given undergoing chemical reaction is is rewritten below:

2Al (s) + 3H_2SO_4 (aq)\rightarrow  Al _2(SO4)_3 (aq) + 3H_2 (g)

By stoichiometry we find the minimum mass of H2SO4 (in g) as shown below:

m_{H_2SO_4}=15.0gAl*\frac{1molAl}{27gAl}*\frac{3molH_2SO_4}{2molAl}*\frac{98gH_2SO_4}{1molH_2SO_4} \\m_{H_2SO_4}=81.7gH_2SO_4

Moreover, mass of H2 gas (in g) would be produced by the complete reaction of the aluminum block turns out:

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Best regards.

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In the given example, it is obvious that the energy released from 1 gram of uranium is more than that of the energy released from 3 grams of coal because the amount of energy released during nuclear fission is millions of times more efficient per mass than that of coal considering only \frac{1}{10}^{th} part of the original nuclei is converted to energy.

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72.71 . simple google search, you shouldnt waste points

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