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3 years ago

Chemistry, please help! Thanks.

Chemistry

1 answer:

Ilya [14]3 years ago

4 0

Answer:

d. The gold(III) ion is most easily reduced.

Explanation:

The standard reduction potentials are

Au³⁺ + 3e⁻ ⟶ Au; 1.50 V

Hg²⁺ + 2e⁻ ⟶ Hg; 0.85 V

Zn²⁺ + 2e⁻ ⟶ Zn; -0.76 V

Na⁺ + e⁻ ⟶ Na; -2.71 V

A <em>more positive voltage</em> means that there is a <em>stronger driving force</em> for the reaction.

Thus, Au³⁺ is the best acceptor of electrons.

Reduction Is Gain of electrons and, Au³⁺ is gaining electrons, so

Au³⁺ is most easily reduced.

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onsider the following reaction: CaCN2 + 3 H2O → CaCO3 + 2 NH3 105.0 g CaCN2 and 78.0 g H2O are reacted. Assuming 100% efficiency

mestny [16]

Answer : The excess reactant is, $H_2O$

The leftover amount of excess reagent is, 7.2 grams.

Solution : Given,

Mass of $CaCN_2$ = 105.0 g

Mass of $H_2O$ = 78.0 g

Molar mass of $CaCN_2$ = 80.11 g/mole

Molar mass of $H_2O$ = 18 g/mole

Molar mass of $CaCO_3$ = 100.09 g/mole

First we have to calculate the moles of $CaCN_2$ and $H_2O$ .

$\text{ Moles of }CaCN_2=\frac{\text{ Mass of }CaCN_2}{\text{ Molar mass of }CaCN_2}=\frac{105.0g}{80.11g/mole}=1.31moles$

$\text{ Moles of }H_2O=\frac{\text{ Mass of }H_2O}{\text{ Molar mass of }H_2O}=\frac{78.0g}{18g/mole}=4.33moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$CaCN_2+3H_2O\rightarrow CaCO_3+2NH_3$

From the balanced reaction we conclude that

As, 1 mole of $CaCN_2$ react with 3 mole of $H_2O$

So, 1.31 moles of $CaCN_2$ react with $1.31\times 3=3.93$ moles of $H_2O$

From this we conclude that, $H_2O$ is an excess reagent because the given moles are greater than the required moles and $CaCN_2$ is a limiting reagent and it limits the formation of product.

Left moles of excess reactant = 4.33 - 3.93 = 0.4 moles

Now we have to calculate the mass of excess reactant.

$\text{ Mass of excess reactant}=\text{ Moles of excess reactant}\times \text{ Molar mass of excess reactant}(H_2O)$

$\text{ Mass of excess reactant}=(0.4moles)\times (18g/mole)=7.2g$

Thus, the leftover amount of excess reagent is, 7.2 grams.

8 0

3 years ago

A neutron collides with a nitrogen atom, resulting in a transmutation. Balance the equation. Superscript 1 Subscript 0 Baseline

o-na [289]

Answer:

A is 14

Z is 6

X is C

Explanation:

Have a great day!

7 0

3 years ago

What is the wavelength of a photon with an energy of 3.38 x 10-19 J?

irina1246 [14]

Answer:

C. 588 nm

Explanation:

Given parameters:

Energy of the photon = 3.38 x 10⁻¹⁹J

Unknown:

Wavelength of the photon = ?

Solution:

The energy of a photon can be expressed as;

E = $\frac{hc}{wavelength}$

hc = E x wavelength

Wavelength = $\frac{hc }{E}$

h is the Planck's constant = 6.63 x 10⁻³⁴m²kg/s

c is the speed of light = 3 x 10⁸m/s

E is the energy

Wavelength = $\frac{6.63 x 10^{-34} x 3 x 10^{8} }{3.38 x 10^{-19} }$ = 5.89 x 10⁻⁷m

4 0

3 years ago

Read 2 more answers

An ideal gas originally at 0.85 atm and 66°C was allowed to expand until its final volume, pressure and temperature were 94.0mL,

xeze [42]

Answer: The original volume in liters was 0.0707L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 0.85 atm

$P_2$ = final pressure of gas = 456 mm Hg = 0.60 atm (760mmHg=1atm)

$V_1$ = initial volume of gas = ?

$V_2$ = final volume of gas = 94.0 ml

$T_1$ = initial temperature of gas = $66^oC=273+66=339K$

$T_2$ = final temperature of gas = $113^oF=318K$ $(32^0F=273K)$

Now put all the given values in the above equation, we get:

$\frac{0.85\times V_1}{339}=\frac{0.60\times 94.0}{318}$

$V_1=70.7ml=0.0707L$ (1L=1000ml)

Thus the original volume in liters was 0.0707L

8 0

3 years ago

What is the wavelength of a wave having a frequency of 2500 Hz

Lemur [1.5K]

We will assume that the wave is moving in free space, thus, the velocity of the wave would be equal to the speed of light = 3 * 10^8 meters/sec

The velocity of the wave can be calculated using the following rule:
velocity = frequency * wavelength where:
velocity = 3 * 10^8 m/sec
frequency = 2500 Hz
wavelength is the unknown that we want to calculate.

Substitute with the givens in the above equation to get the wavelength as follows:
3 * 10^8 = 2500*wavelength
wavelength = 120 * 10^3 meters

5 0

3 years ago

Read 2 more answers