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4 years ago

An object accelerates from rest to a velocity of 4m/s over a distance of 20m what is the acceleration

Physics

1 answer:

Goshia [24]4 years ago

4 0

Answer:

Data:-vi=0 ,vf=4m/s ,s=20m ,a=?

Explanation:

Solution according to 3rd eq of motion 2as=vf²-vi² here we have to find a so a=vf²-vi²/2s ,a=(4²) -(0)²/2×20 ,a=16/40 ,a=0.4m/sec²

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What real-world examples show no work being done? Can you think of examples other than resisting the force of gravity?

GalinKa [24]

-- pushing on a brick wall

-- standing on your little brother's back so that he can't get up

-- taking a nap while on the job

-- squeezing anything that doesn't yield to your squeeze, such as a glass bottle or your girl friend

-- watching TV

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8 0

3 years ago

Suppose a straight 1.00-mm-diameter copper wire could just "float" horizontally in air because of the force due to the Earth’s m

insens350 [35]

To solve this problem it is necessary to apply the concepts related to the Force since Newton's second law, as well as the concept of Electromagnetic Force. The relationship of the two equations will allow us to find the magnetic field through the geometric relations of density and volume.

$F_{mag}= BIL$

Where,

B = Magnetic Field

I = Current

L = Length

<em>Note: $F_{mag}$ is a direct adaptation of the vector relation $F=q \times V \times B$ </em>

From Newton's second law we know that the relation of Strength and weight is determined as

$F_g = mg$

Where,

m = Mass

g = Gravitational Acceleration

For there to be balance the two forces must be equal therefore

$F_{mag} = F_g$

$BIL = mg$

Our values are given as,

Diameter $(d) = 1.0mm = 1*10^{-3}m$

Radius $(r) = \frac{d}{2} = \frac{1*10^{-3}}{2} = 0.5*10^{-3}m$

Magnetic Field $(B) = 5.0*10^{-5} T$

From the relationship of density another way of expressing mass would be

$\rho = \frac{m}{V} \rightarrow m = \rho V$

At the same time the volume ratio for a cylinder (the shape of the wire) would be

$V = \pi r^2 L \rightarrow L =Length, r= Radius$

Replacing this two expression at our first equation we have that:

$BIL = mg$

$BIL = ( \rho V)g$

$BIL = ( \rho \pi r^2 L)g$

Re-arrange to find I

$I = \frac{( \rho \pi r^2 L)g}{BL}$

$I = \frac{( \rho \pi r^2 )g}{B}$

We have for definition that the Density of copper is $8.9*10^3 Kg/m^3$ , gravity acceleration is $9.8m/s^2$ and the values of magnetic field (B) and the radius were previously given, then:

$I = \frac{( (8.9*10^3 ) \pi (0.5*10^{-3})^2 )(9.8)}{5.0*10^{-5}}$

$I = 1370.05A$

The current is too high to be transported which would make the case not feasible.

8 0

3 years ago

What is the weight of a basketball with a mass of 0.5 kg

IgorLugansk [536]

W = 4.9N. The weight of a basketball with a mass of 0.5Kg is 4.9N.

The weight of an object is the force of gravity on the object and can be defined as the product of the mass by the acceleration of gravity, w = mg.

W = (0.5Kg)(9.8 m/s²) = 4.9N

6 0

3 years ago

A friend of yours who is traveling the world reports that she recently experienced a day on which the surface wind blew from the

klasskru [66]

Answer:

At that time, she was in the southern hemisphere

Explanation:

She is witnessing the southeastern trade breeze because the cloud is passing from east to west and she is also witnessing a storm from the southeast.

Because of the Coriolis effect, which deviates the atmosphere in the left-hand side of the southern hemisphere and generates a southeastern wind, this wind did not blow directly from south to east.

4 0

3 years ago

A graph with resistance in ohms on the x-axis from 0 to 200 and current in amps on the y-axis from 0 to 5. The graph is labeled

Dafna1 [17]

Answer:

1. decreases

2. inverse proportionality

3. 1 A

Explanation

Just did it

5 0

3 years ago