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Ann [662]
3 years ago
8

Which term describes a possible explanation of, or answer to, a scientific question that is based on prior knowledge or research

and that is testable?
Physics
2 answers:
Daniel [21]3 years ago
8 0

Answer:

Hypothesis

Explanation:

suter [353]3 years ago
3 0
I think it would be called a hypothesis.
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How much positive electric charge is in 10 moles of carbon? NA=6.022×1023mol−1, e=1.60×10−19C.
levacccp [35]

Answer:

4.75 x 10^-25 kg

Explanation:

5 0
3 years ago
1. A 1.30 kg ball strikes a wall with a velocity of -10.5 m/s. The ball bounces off with a velocity of 6.50 m/s. If the ball is
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Let F be the magnitude of the force. The impulse of this force while the ball is in contact with the wall is

Ft = F (0.0210 s)

and this impulse is equal to the change in the ball's momentum,

m ∆v = (1.30 kg) (6.50 m/s - (-10.5 m/s)) = (1.30 kg) (17.0 m/s)

Solve for F :

F (0.0210 s) = (1.30 kg) (17.0 m/s)

F = (1.30 kg) (17.0 m/s) / (0.0210 s)

F ≈ 1050 N

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3 years ago
If the strings have different thicknesses, which of the following parameters, if any, will be different in the two strings?.
cricket20 [7]

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Wave speed and wavelength

Explanation:

6 0
3 years ago
Two blocks of clay, one of mass 100 kg and one of mass 3.00 kg, undergo a completely inelastic collision. Before the collision o
adoni [48]

Answer:

a)  v = 0.8 m / s , b)  v_{f} = 0.777 m / s , c) ΔK = 0.93 J

Explanation:

This exercise can be solved using the concepts of moment, first let's define the system as formed by the two blocks, so that the forces during the crash have been internal and the moment is conserved.

They give us the mass of block 1 (m1 = 100kg, its kinetic energy (K = 32 J), the mass of block 2 (m2 = 3.00 kg) and that it is at rest (v₀₂ = 0)

 

Before crash

     po = m1 vo1 + m2 vo2

     po = m1 vo1

After the crash

     p_{f} = (m1 + m2) v_{f}

a) The initial speed of the block of m1 = 100 kg, let's use the kinetic energy

     K = ½ m v²

     v = √2K / m

     v = √ (2 32/100)

     v = 0.8 m / s

b) The final speed,

    p₀ = p_{f}

    m1 v₀1 = (m1 + m2) v_{f}

   v_{f} = m1 / (m1 + m2) v₀₁

The initial velocity is calculated in the previous part v₀₁ = v = 0.8 m / s

    v_{f} = 100 / (3 + 100) 0.8

   v_{f} = 0.777 m / s

c) The change in kinetic energy

Initial      K₀ =K_{f}

              K₀ = 32 J

Final       K_{f} = ½ (m1 + m2) v_{f}²

              K_{f}= ½ (3 + 100) 0.777²

              K_{f} = 31.07 J

              ΔK = K_{f} - K₀

              ΔK = 31.07 - 32

              ΔK = -0.93 J

As it is a variation it could be given in absolute value

Part D

For this part s has the same initial kinetic energy K = 32 J, but it is block 2 (m2 = 3.00kg) in which it moves

d) we use kinetic energy

        v = √ 2K / m2

        v = √ (2 32/3)

        v = 4.62 m / s

e) the final speed

      v₀₂ = v =  4.62 m/s  

      p₀ = m2 v₀₂

      m2 v₀₂ = (m1 + m2) v_{f}

      v_{f} = m2 / (m1 + m2) v₀₂

      v_{f} = 3 / (100 + 3) 4.62

      v_{f} = 0.135 m / s

f) variation of kinetic energy

     K_{f} = ½ (m1 + m2) v_{f}²

     K_{f} = ½ (3 + 100) 0.135²

     K_{f} = 0.9286 J

     ΔK = 0.9286-32

    ΔK = 31.06 J

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3 years ago
Which of the following is an accurate description of the amplitude of a wave?
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The amplitude of the wave is the 'full height of the wave.' Amplitude is measured in m (meters) and is measured over the change of a single period.
3 0
4 years ago
Read 2 more answers
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