1.5 m/s is the velocity.
9.3 m is the length of aisle, over which Distance will be covered.
Time is demanded in which the child will move the cart over the aisle with 1.5 m/s.
v=S/t
and,
t=S/v
Put values,
t=9.3/1.5=6.2 s
Answer
given,
time = 10 s
ship's speed = 5 Km/h
F = m a
a is the acceleration and m is mass.
In the first case
F₁=m x a₁
where a₁ = difference in velocity / time
F₁ is constant acceleration is also a constant.
Δv₁ = 5 x 0.278
Δv₁ = 1.39 m/s
![a_1=\dfrac{1.39}{10}](https://tex.z-dn.net/?f=a_1%3D%5Cdfrac%7B1.39%7D%7B10%7D)
a₁ = 0.139 m/s²
F₂ =m x a₂
F₃ = F₂ + F₁
Δv₃ = 19 x 0.278
Δv₃ = 5.282 m/s
a₃=Δv₂ / t
![a_3=\dfrac{5.282}{10}](https://tex.z-dn.net/?f=a_3%3D%5Cdfrac%7B5.282%7D%7B10%7D)
a₃ = 0.5282 m²/s
m a₃=m a₁ + m a₂
a₃ = a₂ + a₁
0.5282 = a₂ + 0.139
a₂=0.3892 m²/s
F₂ = m x 0.3892...........(1)
F₁ = m x 0.139...............(2)
F₂/F₁
ratio = ![\dfrac{0.3892}{0.139}](https://tex.z-dn.net/?f=%5Cdfrac%7B0.3892%7D%7B0.139%7D)
ratio = 2.8
Answer: Peak-to-peak voltage is the distance from the lowest negative amplitude, or trough, to the highest positive amplitude, or crest, of the AC voltage waveform. In other words, peak-to-peak voltage is equal to the full height of the waveform. Peak-to-peak voltage can be found using peak voltage or RMS voltage.
Explanation:hope tht gave u a clue have a wonderful Christmas Eve time with your family!❄️