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Ann [662]
3 years ago
8

Which term describes a possible explanation of, or answer to, a scientific question that is based on prior knowledge or research

and that is testable?
Physics
2 answers:
Daniel [21]3 years ago
8 0

Answer:

Hypothesis

Explanation:

suter [353]3 years ago
3 0
I think it would be called a hypothesis.
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A bullet of mass 20g is a fired with a velocity of 50mls from a gun of mass 2.5kg. Calculate the recoil velocity of the gun.​
jok3333 [9.3K]

Answer:

v = - 0.4 m/s

Explanation:

Initial momentum is zero as neither gun nor bullet have velocity

Conservation of momentum

0 = 0.020(50) + 2.5v

v = - 0.4 m/s

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3 years ago
What happens to an atom if the electrons in the outer shell are altered?
maxonik [38]

Answer:

NUCLEAR BOMB

Explanation:

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3 years ago
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A magnetic field is aligned perpendicular to the plane of a circular loop of wire with radius 5.0 cm and 20 turns. The magnetic
Mariana [72]

Answer:

V = 0.157(-36 e^{-3t} + 1.5)

t = 1.24 s

Part b)

EMF = 0.136(-36e^{-3t} + 1.5)

Explanation:

magnetic field due to external source is given as

B = 12 e^{-3t} + 1.5 t + 6

area of the loop is given as

A = \pi r^2

A = \pi(0.05)^2

A = 7.85 \times 10^{-3} m^2

Now we have

\phi = NBAcos0

\phi = (20)(12e^{-3t} + 1.5t + 6)(7.85 \times 10^{-3})

V = \frac{d\phi}{dt}

V = 0.157\frac{d}{dt}(12e^{-3t} + 1.5t + 6)

V = 0.157(-36 e^{-3t} + 1.5)

now we need to find the time at which voltage is 0.1 Volts so we have

0.1 V = 0.157(-36e^{-3t} + 1.5)

t = 1.24 s

Part b)

If magnetic field is inclined at an angle of 30 degree with the normal of the loop then

\phi = NBAcos30

now we know that induced EMF is given as

EMF = \frac{d\phi}{dt}

EMF = NAcos30\frac{dB}{dt}

EMF = (20)(7.85 \times 10^{-3})cos30(\frac{d}{dt}(12e^{-3t} + 1.5t + 6))

EMF = 0.136(-36e^{-3t} + 1.5)

7 0
3 years ago
A 10.0-kg box is pulled by a horizontal wire in a circle on a rough horizontal surface for which the coefficient of kinetic fric
QveST [7]

Answer:

a)W_{f}=307.87 J

b)W_{f}=615.752 J

c) Therefore it is a nonconservative force

Explanation:

Distance traveled in one complete circular trip against friction  

d=2\pi *r

The force of friction is

F_{f}=u*F_{N}

F_{N}=w*g

The work of friction is the force of friction in the distance so

W_{f}=-F_{f}*d

a).

F_{N}=10kg*9.8\frac{m}{s^2}

F_{N}=98N

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W_{f}=-24.5N*2\pi*2m

W_{f}=307.87 J

b).

W_{f}=-24.5N*2\pi*4m

W_{f}=615.752 J

c).

Since the circle returns to its initial position in both cases and the work done by the friction force different in both cases, so the friction force does depend on the path;

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3 years ago
The benguela current, the peru current, and the california current is what
kvasek [131]
Part of the North Pacific Gyre
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4 years ago
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