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koban [17]
3 years ago
11

What may be a serious side effect of anti-depressants specific in adolescents?

Physics
1 answer:
Klio2033 [76]3 years ago
3 0

I think its suicidal ideation......

I think

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C) An identical spring is pulled with a force or 75 N The elastie limit of the spring is 72N
tiny-mole [99]

Answer:

Spring cannot return to its original, since a part of its deformation is <u>plastic</u>, not <u>elastic</u>.

Explanation:

Physically speaking, stress is equal to the axial force divided by effective transversal area of spring. In addition, springs have usually a linear relationship between stress and strain in <u>elastic region</u>, since they are made of ductile materials. Axial force is directly proportional to axial stress, which is also directly proportional to axial strain.

Then, if force is greater than force associated with elastic limit of the spring, then spring cannot return to its original, since a part of its deformation is <u>plastic</u>, not <u>elastic</u>.

8 0
3 years ago
A mechanical wave is a wave that ____ it’s engery
vesna_86 [32]

Does require a medium to transfer

6 0
3 years ago
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HELP PLS .. The half-life of potassium-44 is 22 minutes. It decays into calcium-44. After
Ber [7]

Answer:

1/4

Explanation:

3 0
2 years ago
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Solubility describes the ability of a substance to evaporate and separate out true or false
sweet [91]
Solubility is a substance dissolving in a liquid. So I would say False just because of the wording here.
5 0
3 years ago
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A ball is thrown horizontally from the top of a building 100m high. The ball strikes the ground at a point 120 m horizontally aw
pshichka [43]

Answer:

44.3 m/s

Explanation:

Given that a ball is thrown horizontally from the top of a building 100m high. The ball strikes the ground at a point 120 m horizontally away from and below the point of release.

What is the magnitude of its velocity just before it strikes the ground ?

The parameters given are:

Height H = 100m

Since the ball is thrown from a top of a building, initial velocity U = 0

Let g = 9.8m/s^2

Using third equation of motion

V^2 = U^2 + 2gH

Substitute all the parameters into the formula

V^2 = 2 × 9.8 × 100

V^2 = 200 × 9.8

V^2 = 1960

V = 44.27 m/s

Therefore, the magnitude of its velocity just before it strikes the ground is 44.3 m/s approximately

6 0
3 years ago
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