W = F x d
F: 450 N
d = 10 m
plug your variables into the equation to get W = 450N x 10m
Sonography is most likely because it has good resolution without radiation.
Use v^2 - u^2 = 2as
Here, u = 20 m/s , a = -0.5 m/s^2 and v = 0
- 400 = -s ======> s = 400 m
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The right answer for the question that is being asked and shown above is that:
(1) <span>b. the light will reach the front of the rocket at the same instant that it reaches the back of the rocket.
</span>(2) <span>a. the light will reach the front of the rocket before it reaches the back of the rocket.
</span>(3) <span>b. less than Δt
</span>(4) <span>c. the length of your spaceship is getting longer.
(5) </span><span>c. 1.20c</span>
Answer:
Gravitational potential energy (GPE) = 107.8J
Explanation:
Gravitational potential energy (GPE) = mgh
Where mass(m) = 11kg
Acceleration due to gravity(g) = 9.8m²/s
height = assumed to be 1m
Force(F) = mg
Force(F) = 11×9.8 = 107.8N
Gravitational potential energy (GPE) = 107.8×1
= 107.8J