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Pepsi [2]
3 years ago
14

A student performing a double-slit experiment is using a green laser with a wavelength of 550 nm. She is confused when the m = 5

maximum does not appear. She had predicted that this bright fringe would be 1.6 cm from the central maximum on a screen 1.5 m behind the slits. What is the width of her slits?
Physics
1 answer:
sweet [91]3 years ago
3 0

Answer:

d = 52 μm

Explanation:

given,

wavelength of the light source (λ)= 550 nm

distance to form interference pattern(D) = 1.5 m

y = 1.6 cm = 0.016 m

width of the slits = ?

now, using displacement formula

 y = \dfrac{m\lambda\ D}{d}

for the first maxima, m = 1

 d = \dfrac{1\times \lambda\ D}{y}

 d = \dfrac{1\times  550 \times 10^{-9}\times 1.5}{0.016}

       d = 5.2 x 10⁻⁶ m

       d = 52 μm

hence, the width of her slits is equal to d = 52 μm

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Explanation:

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This should be your answer.

7 0
3 years ago
. An object has a position given by ~r(t) = [3.0 m − (4.00 m/s)t]ˆı + [6.0 m − (8.00 m/s2 )t 2 ]ˆ , where all quantities are in
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(c) 16 m/s²

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The velocity is the first time-derivative of <em>r(t).</em>

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3 years ago
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