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3 years ago

5

A box is lowered using a rope. If the acceleration of the box, is 2.5 m/s2 (downward) and the tension in the rope is 31 N, what

is the mass of the box (in kg)?

1 answer:

Thepotemich [5.8K]3 years ago

4 0

F= ma
31-mg = m(-2.5m/s2)
31= mg-2.5 m
31 = m*(9.8m/s2 -2.5 m/s2)
31 = 7.3 m
m = 31/7.3
m = 4.25 kg

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