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3 years ago

When you divide the mass of a substance by its volume, you get its.

Chemistry

2 answers:

Zarrin [17]3 years ago

8 0

Answer:Density

Explanation:

ziro4ka [17]3 years ago

4 0

Answer:density

Explanation:

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Wassup everyone?????

ioda

Answer:

I'm good

Explanation:

What about you?

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3 years ago

Element

Alexeev081 [22]

helium

has the most neutrons in the nucleus

7 0

3 years ago

Read 2 more answers

How many grams of XeF6 are required to react with 0.579 L of hydrogen gas at 4.46 atm and 45°C in the reaction shown below?

natka813 [3]

Answer:

8.1433 g of XeF₆ are required.

Explanation:

Balanced chemical equation;

XeF₆ (s) + 3H₂ (g) → Xe (g) + 6HF (g)

Given data:

Volume of hydrogen = 0.579 L

Pressure = 4.46 atm

Temperature = 45 °C (45+273= 318 k)

Solution:

First of all we will calculate the moles of hydrogen

PV = nRT

n = PV/ RT

n = 4.46 atm × 0.579 L / 0.0821 atm. dm³. mol⁻¹. K⁻¹ × 318 K

n = 2.6 atm . L / 26.12 atm. dm³. mol⁻¹

n = 0.0995 mol

Mass of hydrogen:

Mass = moles × molar mass

Mass = 0.0995 mol × 2.016 g/mol

Mass = 0.2006 g

Now we will compare the moles of hydrogen with XeF₆ from balance chemical equation.

H₂ : XeF₆

3 : 1

0.0995 : 1/3× 0.0995 = 0.0332 mol

Now we will calculate the mass of XeF₆.

Mass = moles × molar mass

Mass = 0.0332 mol × 245.28 g/mol

Mass = 8.1433 g

4 0

3 years ago

A metal used in hot water systems

Basile [38]

Answer:

I think this would be iron

Explanation:

5 0

2 years ago

Balance the equation and show the calculation of the number of moles and grams of CO2 formed from 11.9 grams of O2. Show your an

n200080 [17]

Answer:

0.2349 moles, 10.3356 g

Explanation:

The given reaction is :

$C_6H_{14}+O_2\rightarrow CO_2 + H_2O$

The balanced reaction by equating the same number of each atom both side is :

$2C_6H_{14}+19O_2\rightarrow 12CO_2 + 14H_2O$

Given that :

Amount of oxygen gas = 11.9 g

Molar mass of oxygen gas = 32 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus, moles are:

$moles= \frac{11.9\ g}{32\ g/mol}$

$moles= 0.3719\ mol$

From the reaction,

19 moles of oxygen gas on reaction forms 12 moles of carbon dioxide

Also,

1 mole of oxygen gas on reaction forms 12/19 moles of carbon dioxide

So,

0.3719 moles of zinc on reaction forms $\frac {12}{19}\times 0.3719$ mole of carbon dioxide

<u>Moles of carbon dioxide formed = 0.2349 moles</u>

Mass of carbon dioxide = moles×Molar mass

Molar mass of carbon dioxide = 44 g/mol

<u>Mass of carbon dioxide formed = 0.2349 ×44 g = 10.3356 g</u>

4 0

3 years ago