Answer:
The correct answer should be
A. 20 Joules
Explanation:
I'm taking the K12 Unit Test: Energy - Part 1 right now
Answer:
Microlensing.
Explanation:
This techniques is called Microlensing.
Microlensing is a method of gravitational lensing where light from a backdrop point of origin is curved to develop distorted, numerous and/or lightened images by the gravity field of a foreground lens.
This method is very effective in discovering planets that are far-far from earth.It is actually an astronomical effect that was predicted by Albert Einstein's general theory of relativity.
Big band is music group (a group of people who perform instrumental and/or vocal music ) playing jazz or jazz-influenced popular music and which was popular during the Swing Era from the mid-1930s until the late 1940s. These big bands contained saxophones, trumpets, trombone and other instruments and typically consisted of approximately 12 to 25 musicians.
Answer:
<h2>The amount of torque put on the car is 33,000Nm</h2>
Explanation:
Formula for calculating torque is expressed as T = rFsin
where;
r is the radius of the of the arm of the jack = 3m
F is the force exerted = 11000
is the angle of rotation = 90°
On substituting;
![T = 3*11000sin90^{o} \\T = 3*11000 (sin90^{o} =1)\\T = 33000Nm](https://tex.z-dn.net/?f=T%20%3D%203%2A11000sin90%5E%7Bo%7D%20%5C%5CT%20%3D%203%2A11000%20%28sin90%5E%7Bo%7D%20%3D1%29%5C%5CT%20%3D%2033000Nm)
To solve this problem we will apply the principle of conservation of energy. For this purpose, potential energy is equivalent to kinetic energy, and this clearly depends on the position of the body. In turn, we also note that the height traveled is twice that of the rigid rod, therefore applying these concepts we will have
![KE = PE](https://tex.z-dn.net/?f=KE%20%3D%20PE)
![\frac{1}{2} mv^2 = mgh](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20mv%5E2%20%3D%20mgh)
![v = \sqrt{2gh}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B2gh%7D)
![v = \sqrt{2(9.8)(2(55.8*10^{-2}))}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B2%289.8%29%282%2855.8%2A10%5E%7B-2%7D%29%29%7D)
![v = 4.67m/s](https://tex.z-dn.net/?f=v%20%3D%204.67m%2Fs)
Therefore the minimum speed at the bottom is required to make the ball go over the top of the circle is 4.67m/s