Greg is in a bike race. At mile marker four (out of ten), his speed was measured at 13.5 mph.

Physics

2 answers:

Andreyy893 years ago

8 0

It is the instantaneous speed of the bike rider.

Explanation:

At the mile marker, the measured speed gives the instantaneous speed of the bike rider.

The instantaneous speed is speed measured at a precise or instance of time.

Speed is the rate of change of distance with time. It is a scalar quantity that only shows magnitude with no reference to direction.

Velocity is the displacement divided by time. It has both magnitude and directions.

Average speed is measured over a period of time as the distance increases from the starting point.

From this, we can see that 13.5mph is the instantaneous speed of the bike rider.

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Instantaneous velocity brainly.com/question/2234298

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Leya [2.2K]3 years ago

8 0

Answer:

B: it is the instantaneous speed of the bike rider.

Explanation:

keep it going....

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A force in the +x-direction with magnitude ????(x) = 18.0 N − (0.530 N/m)x is applied to a 6.00 kg box that is sitting on the ho

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Answer:

$v_f=8.17\frac{m}{s}$

Explanation:

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$W=\int\limits^{x_f}_{x_0} {F(x)} \, dx \\W=\int\limits^{14}_{0} ({18N-0.530\frac{N}{m}x}) \, dx\\W=[(18N)x-(0.530\frac{N}{m})\frac{x^2}{2}]^{14}_{0}\\W=(18N)14m-(0.530\frac{N}{m})\frac{(14m)^2}{2}-(18N)0+(0.530\frac{N}{m})\frac{0^2}{2}\\W=252N\cdot m-52N\cdot m\\W=200N\cdot m$

Since we have a frictionless surface, according to the the work–energy principle, the work done by all forces acting on a particle equals the change in the kinetic energy of the particle, that is:

$W=\Delta K\\W=K_f-K_i\\W=\frac{mv_f^2}{2}-\frac{mv_i^2}{2}$