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erica [24]
3 years ago
12

we know if we apply the force along the left, friction acts along the right and vice versa.But what about an object which is not

moving but at rest on a surface?​
Physics
1 answer:
myrzilka [38]3 years ago
5 0

Answer:

<em>Explanation below</em>

Explanation:

<u>Friction Force</u>

When two objects are in contact, the surface between them exerts a frictional force as long as the objects are tried to move with respect to each other.

If a given external force is applied to the left, then a friction force appears to the right and opposes the intent to move them. A similar situation occurs when the force is applied to the right side.

If the object is at rest and no force is applied, no friction force appears.

It's important to recall that two different friction forces are defined: the kinetic friction force and the static friction force, usually the latter is greater than the first.

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As computer information technology becomes faster, how does the ability of scientists to collect and organize data change?
irina1246 [14]
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7 0
3 years ago
La tensión en newtons necesaria para que una onda transversal cuya longitud de onda es 3.33 cm vibre a razón de 625 ciclos por s
NemiM [27]

Answer:

9.34 N

Explanation:

First of all, we can calculate the speed of the wave in the string. This is given by the wave equation:

v=f \lambda

where

f is the frequency of the wave

\lambda is the wavelength

For the waves in this string we have:

f=625 Hz, since it completes 625 cycles per second

\lambda=3.33 cm = 0.033 m is the wavelength

So the speed of the wave is

v=(625)(0.0333)=20.6 m/s

The speed of the waves in a string is related to the tension in the string by

v=\sqrt{\frac{T}{\mu}} (1)

where

T is the tension in the string

\mu=\frac{m}{L} is the linear density

In this problem:

m=16.5 g = 16.5\cdot 10^{-3} kg is the mass of the string

L = 0.75 m is the its length

Solving the equation (1) for T, we find the tension:

T=\mu v^2 = \frac{m}{L} v^2 = \frac{16.5\cdot 10^{-3}}{0.75}(20.6)^2=9.34 N

8 0
3 years ago
20 points<br> Which BEST replaces the question mark?<br><br> In Saudi Arabia, __________?
dsp73
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3 0
3 years ago
A dragster starts from rest and travels 1/4 mi in 6.80 s with constant acceleration. What is its velocity when it crosses the fi
Ahat [919]
<h2>Its velocity when it crosses the finish line is 117.65 m/s</h2>

Explanation:

We have equation of motion s = ut + 0.5 at²

        Initial velocity, u = 0 m/s

        Acceleration, a = ?

        Time, t = 6.8 s    

        Displacement, s = 1/4 mi =    400 meters

     Substituting

                      s = ut + 0.5 at²

                      400 = 0 x 6.8 + 0.5 x a x 6.8²

                      a = 17.30 m/s²

Now we have equation of motion v = u + at

     Initial velocity, u = 0 m/s

     Final velocity, v = ?

     Time, t = 6.8 s

      Acceleration, a = 17.30 m/s²

     Substituting

                      v = u + at  

                      v = 0 + 17.30 x 6.8

                      v = 117.65 m/s

Its velocity when it crosses the finish line is 117.65 m/s

6 0
3 years ago
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Novosadov [1.4K]

Answer:

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Explanation:

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2 years ago
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