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irinina [24]
2 years ago
7

What must be the distance in meters between point charge q1 = 30.3 µC and point charge q2 = -68.2 µC for the electrostatic force

between them to have a magnitude of 7.09 N?
Physics
1 answer:
Zolol [24]2 years ago
4 0

Answer: 1.62 m

Explanation: In order to solve this problem we have to use the definition of Coulomb force whic is given by:

F=(k*q1*q2)/d^2  where k is a constant 9*10^9 N/C^2*m^2. d is the distance between tha charges q1 and q2.

then we can:

d^2= (k*q1*q2)/F= (9*10^9*30.3*10^-6*68.2*10^-6)/7.09=1.62 m

(note we have  considered q2 as positive because we are determining d^2 by using the magnitude of the electric Force bewteen the charges).

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If the frequency of sound is doubled, how will its speed change? how will its wavelength change?
eimsori [14]

From the given equation we can deduce what changes will occur if the frequency of the sound is doubled

V= f (λ)

Speed = frequency. Wavelength  

When the frequency is doubled, speed will not change. Because speed depends on factors like temperature, air pressure, density of the gas. Since all these factors are unchanged thus speed will remain unchanged

Frequency is the number of waves produced per second. Frequency and wavelength are inversely proportional .Thus, if the frequency is doubled the wavelength would be halved.


6 0
3 years ago
A particle traveling in a circular path of radius 300 m has an instantaneous velocity of 30 m/s and its velocity is increasing a
hodyreva [135]

Answer:

5 m/s2

Explanation:

The total acceleration of the circular motion is made of 2 components: centripetal acceleration and linear acceleration of 4 m/s2. They are perpendicular to each other.

The centripetal acceleration is the ratio of instant velocity squared and the radius of the circle

a_c = \frac{v^2}{r} = \frac{30^2}{300} = \frac{900}{300} = 3 m/s^2

So the magnitude of the total acceleration is

a = \sqrt{a_c^2 + a_l^2} = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5 m/s^2

4 0
3 years ago
Consider a heat pump that operates on the reversed Carnot cycle with R-134a as the working fluid executed under the saturation d
Schach [20]

Answer:

Work out = 28.27 kJ/kg

Explanation:

For R-134a, from the saturated tables at 800 kPa, we get

h_{fg} = 171.82 kJ/kg

Therefore, at saturation pressure 140 kPa, saturation temperature is

T_{L} = -18.77°C = 254.23 K

At saturation pressure  800 kPa, the saturation temperature is

T_{H} = 31.31°C = 304.31 K

Now heat rejected will be same as enthalpy during vaporization since heat is rejected from saturated vapour state to saturated liquid state.

Thus, q_{reject} = h_{fg} = 171.82 kJ/kg

We know COP of heat pump

COP = \frac{T_{H}}{T_{H}-T_{L}}

        = \frac{304.31}{304.31-254.23}

         = 6.076

Therefore, Work out put, W = \frac{q_{reject}}{COP}

                                              = 171.82 / 6.076

                                              = 28.27 kJ/kg

8 0
3 years ago
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1 gram per cubic centimeter is equal to 1000 kilograms per cubic meter. Just multiply it with a 1000 and you have your solution.
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Why does atmospheric pressure decrease with altitude.
ella [17]

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