Answer:
the new acceleration will be six times the initial acceleration
Explanation:
A mass m1 is hung from a spring oscillates on a spring with spring constant k1. The amplitude of its motion is A1 and it has a maximum magnitude acceleration a1. If the mass is doubled, the spring constant tripled, and the amplitude quadrupled, what will the new maximum magnitude acceleration be
mass =m1 acceleration
f=force applied
k=force constant
x=extension. amplitude or compression
a=
from hooke's law we know that the force exerted on an elastic material is directly proportional to the extension provided that the elastic limit is not exceeded
f=kx
m*a=k*x
a1=kx/m1
m2=2m1
k2=3k1
x2=4x1
substituing into the initial equation
a2=3k1*4x1/2m1
a2=6k1x1/m1
a2=6a1
the new acceleration will be six times the initial acceleration
