Answer:
So, at the depth of 24 cm below the surface of the glycerine the pressure is 2970 Pa. Hence, this is the required solution.
Explanation:
Given that,
Pressure exerted by the surface of glycerine, P = 2970 Pa and it is greater than atmospheric pressure.
The density of glycerine,
We need to find the depth h below the surface of the glycerine. The pressure due to some depth is given by :
h = 0.24 meters
or
h = 24 cm
Answer:
I= 20 i {N.s}
Explanation:
In order to obtain the impulse on the 2 kg ball, you have to apply the equation of Impulse:
I=FΔt
Where I is the impulse vector, F is the net force and Δt is the interval of time when the force is applied.
In this case:
Δt=0.01 s
F= 2000 i N
where i is the unit vector in the x direction.
Replacing the values in the formula:
I=(2000)(0.01)i
Therefore:
I= 20 i {N.s}
Answer;
=84 kwh
Explanation;
Electrical energy = 1000 watts
1000 watt = 1 kilo watt
1 week = 7 days
Number of hours = 7 × 12× = 84 hours
Consumption
= 1 kw × 84 hours
= 84 kwh
Answer:
D. must have a moon
Explanation:
Scientists say that a planet must orbit a star, must be round, and must be big enough so its gravity clears its orbit of other objects. Therefore, the statement that is not a requirement for a planet is
D. must have a moon
For example, Mercury and Venus are planets with no moons.
Answer:
Period of oscillation = 1.33 seconds
Explanation:
The period of oscillation is given by:
T = 2π√[I/(MgL)]
for I = 2MR² and L = R,
Given: L = 0.22m = R
T = 2π√[2R/g]
T = 2 × 3.142 Sqrt[( 2 × 0.22)/ 9.8]
T = 6.284 Sqrt(0.44/9.8)
T = 6.284 Sqrt(0.0449)
T = 6.284 × 0.2119
T = 1.33 sec
