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Sindrei [870]
3 years ago
15

Need a little help here :(

Physics
2 answers:
Goshia [24]3 years ago
8 0

Answer:

The output out be 200

Explanation:

Hope this helps :))

CaHeK987 [17]3 years ago
5 0

Answer:

1600 lb

Explanation:

The pressure on Ram Input A is the same pressure on the Output Ram.

P₁ = P₂

F₁ / A₁ = F₂ / A₂

F₁ / (π d₁²/4) = F₂ / (π d₂² / 4)

F₁ / d₁² = F₂ / d₂²

(100 lb) / (0.5 in)² = F / (2 in)²

F = 1600 lb

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Answer:

(a). Check attachment.

(b). 280.305 J.

(c). 31.81 kpa; 38.26K.

(d). 24.05K.

(e). 24.05k; 40kpa.

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(a). Kindly check the attached picture for the diagram showing the four process.

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2 - 3 = Isochoric process.

3 - 4 = isothermal process.

4 - 1 = isochoric process.

(b). Recall that the process from 1 to is an adiabatic expansion process.

NB: b = 5/3 for a monoatomic gas.

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= ( 1/ 1 - 5/3) [ (101 × 5^5/3) × 10^1 -5/3] - 101 × 5.

Thus, the workdone = 280.305 J.

(c). P2 = P1 × V1^b/ V2^b = 101 × 5^5/3/ 10^5/3 = 31.81 kpa.

T2 = P2 × V2/ R × 1 = 31.81 × 10/ 8.324 = 38.36k.

(d). The process 2 - 3 is an Isochoric process, then;

T3 = T2/P2 × P3 = 38.26/ 31.82 × 20 = 24.05K.

(e). The process 3 - 4 Is an isothermal process. Then, the temperature at 4 will be the same temperature at 3. Tus, we have the temperature; point 3 = point 4 = 24.05k.

The pressure can be determine as below;

P4 = P3 × V3/ V4 = 20 × 10/ 5 = 200/ 5 = 40 kpa.

(f) workdone = xRT ln( v4/v3) = 1 × 8.314 × 24.05 × ln (5/10) = - 138.6 J

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