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Norma-Jean [14]
3 years ago
9

You throw a small toy ball that is covered with suction cups at the center of your glass patio door. When it hits it sticks to t

he glass, and because the door was not latched, it causes the door to swing open with an angular velocity of 0.19 rad/s. If the ball has a mass of 120 g and the patio door can be treated as a uniform box that is 2.3 m high, 1.0 m wide, and 0.030 m thick with a mass of 7.5 kg what speed did you throw the ball at
Physics
1 answer:
Natali [406]3 years ago
6 0

Answer:

Explanation:

moment of inertia of the door M = 1 /3 m ( l² + b² + d² )

= 1 / 3 x 7.5 x ( 2.3² + 1² + .03² )

= 1 / 3 x 7.5 x 6.2909

I = 15.7272.

moment of inertia of the door + small toy

15.7272 + .12 x .5²

= 15.7272 + .03

= 15.7572

Applying conservation of angular momentum law

mvr = M ω

m is mass of the toy thrown with velocity v at distance r from the axis , M is moment of inertia of door + toy and ω is angular velocity ith which door opens.

.12 x v x .5 =  15.7572 x .19

v = 49.89 m /s .

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