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NeX [460]
3 years ago
13

You wad up a piece of paper and throw it into the wastebasket. How far will

Physics
2 answers:
vitfil [10]3 years ago
6 0

The range of the piece of paper is C) 1.4 m

Explanation:

The motion of the piece of paper is the motion of a projectile, which consists of two separate motions:

- A uniform motion along the horizontal direction, with constant velocity

- A uniformly accelerated motion along the vertical direction, with constant acceleration (the acceleration of gravity, g=9.8 m/s^2)

From the equation of motion, it is possible to find an expression for the range (the total horizontal distance covered) of a projectile, which is given by:

d=\frac{u^2 sin 2\theta}{g}

where

u is the initial velocity

\theta is the angle of projection

g is the acceleration of gravity

For the piece of paper in this problem,

u = 4.3 m/s

\theta=65^{\circ}

Substituting,

d=\frac{(4.3)^2 sin(2\cdot 65^{\circ})}{9.8}=1.45 m \sim 1.4 m

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

aksik [14]3 years ago
4 0

Answer:

like the other person said, the answer is 1.4 m

Explanation:

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The answers are to small to see.

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At what point of thermometric scale does Kelvin scale reading coincide with Fahrenheit scale
amid [387]

Answer:

<em>At 574.59 Kelvin, the Fahrenheit temperature will be 574.59 °F.</em>

Explanation:

We first need to find a relation between the Kelvin scale and the Fahranheit scale. We'll use the Celsius scale to relate them.

The Kelvin and Celsius scales are related by the formula:

K = °C + 273.15

Solving for °C:

°C = K - 273.15

Besides, the Kelvin and Celsius scales are related by:

°C = 5 ⁄ 9(°F - 32)

Now we find a temperature, say X, where both scales coincide. Equating both formulas:

X - 273.15=5 ⁄ 9(X - 32)

Multiply by 9:

9X - 2,458.35 = 5X - 160

Simplifying:

4X = 2,458.35 - 160=2,298.35

Solving:

X =2,298.35 / 4 = 574.59

At 574.59 Kelvin, the Fahrenheit temperature will be 574.59 °F.

3 0
3 years ago
Suppose earth's mass increased but earth's diameter didn't change. Describe how the gravitational force between Earth and the ob
zheka24 [161]

Answer:

It increases proportionally

Explanation:

The gravitational force between the Earth and an object on its surface is given by

F=G\frac{Mm}{R^2}

where

G is the gravitational constant

M is the Earth's mass

m is the mass of the object

R is the Earth's radius

In this problem, the Earth's mass is increased, while the diameter (and therefore, the radius) doesn't change. From the equation, we see that the gravitational force is directly proportional to the Earth's mass: therefore, if the mass is increased, the force will increase as well by the same proportion (for example, if the mass is doubled, the force will double as well)

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The velocity of a passenger relative to a boat is -vpb. The velocity of the boat relative to the river it is moving on is vbr. T
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Answer:

vps = vbr + vrs - vpb

Explanation:

  • If the passenger were at rest, his speed relative to the shore will be identical to the boat's, as follows:
  • vps = vbr + vrs
  • As he is moving in a direction opposite to the boat's, his velocity relative to the shore must be less than if he were at rest, in the same quantity that he was moving opposite to the boat, as follows:
  • vps = vbr+ vrs -vpb
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What is the limitation of relative dating?
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Your not really supposed to date your relative
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