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Andrews [41]
3 years ago
8

We know that there is a relationship between work and mechanical energy change. Whenever work is done upon an object by an exter

nal force (or non-conservative force), there will be a change in the total mechanical energy of the object. If only internal forces are doing work then there is no change in the total amount of mechanical energy. The total mechanical energy is said to be conserved. Think of a real-life situation where we make use of this conservation of mechanical energy (where we can neglect external forces for the most part). Describe your example and speak to both the kinetic and potential energy of the motion.
Physics
1 answer:
solniwko [45]3 years ago
8 0

Answer:

* roller skates and ice skates.

* roller coaster

Explanation:

One of the best examples for this situation is when we are skating, in the initial part we must create work with a force, it compensates to move, after this the external force stops working and we continue movements with kinetic energy, if there are some ramps, we can going up, where the kinetic energy is transformed into potential energy and when going down again it is transformed into kinetic energy. This is true for both roller skates and ice skates.

Another example is the roller coaster, in this case the motor creates work to increase the energy of the car by raising it, when it reaches the top the motor is disconnected, and all the movement is carried out with changes in kinetic and potential energy. In the upper part the energy is almost all potential, it only has the kinetic energy necessary to continue the movement and in the lower part it is all kinetic; At the end of the tour, the brakes are applied that bring about the non-conservative forces that decrease the mechanical energy, transforming it into heat.

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Because the __ signal changes smoothly, like a sine wave, it can closely mimic a human voice. However, part of the signal can ea
Naya [18.7K]

Answer:

Analog,Noise,Digital,less

Explanation:

Analog signal changes continuously with time and moves smoothly.

Due to this analog signal can easily disturbed by noise.

Since digital signal are like square wave due to this digital signals are less affected by noise.

Because the Analog signal changes smoothly, like a sine wave, it can closely mimic a human voice. However, part of the signal can easily get lost to Noise. Because Digital signals are on or off, like a square wave, they best carry information that can easily be converted into numbers. These signals are less affected by noise.

7 0
3 years ago
How do i find minimum potential energy for a roller coaster
Elenna [48]
Don't know about the minimum part, but potential energy is calculated using the following formula:

PE = 9.8 \frac{m}{s^2} * m * h

You need to know the planet (or simply the gravity of the planet), the height of the roller coaster car, and the mass of the car. 

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Like this answer? PM me for more awesome answers! - Boodle
4 0
4 years ago
What can you infer from the statement. velocity is an object is zero
Masteriza [31]
The object is moving at a constant speed
8 0
3 years ago
In February 1955, a paratrooper fell 370 m from an airplane without being able to open his chute but happened to land in snow, s
nevsk [136]

a) 0.94 m

The work done by the snow to decelerate the paratrooper is equal to the change in kinetic energy of the man:

W=\Delta K\\-F d = \frac{1}{2}mv^2 - \frac{1}{2}mu^2

where:

F=1.1 \cdot 10^5 N is the force applied by the snow

d is the displacement of the man in the snow, so it is the depth of the snow that stopped him

m = 68 kg is the man's mass

v = 0 is the final speed of the man

u = 55 m/s is the initial speed of the man (when it touches the ground)

and where the negative sign in the work is due to the fact that the force exerted by the snow on the man (upward) is opposite to the displacement of the man (downward)

Solving the equation for d, we find:

d=\frac{1}{2F}mu^2 = \frac{(68 kg)(55 m/s)^2}{2(1.1\cdot 10^5 N)}=0.94 m

b) -3740 kg m/s

The magnitude of the impulse exerted by the snow on the man is equal to the variation of momentum of the man:

I=\Delta p = m \Delta v

where

m = 68 kg is the mass of the man

\Delta v = 0-55 m/s = -55 m/s is the change in velocity of the man

Substituting,

I=(68 kg)(-55 m/s)=-3740 kg m/s

7 0
3 years ago
Two piles of heavy boxes must be lifted onto a shelf. Each pile has 20 boxes and each box is the same size and weight. Tom and c
Murrr4er [49]
Tom used more Force but over a shorter distance. Tom and Claudia both did the same amount of work.
4 0
4 years ago
Read 2 more answers
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