Answer:
x=5
y=1
Step-by-step explanation:
The substitution method is considered easier because of its simplification.
2x-3y=7 (1)
x+2y=7 (2)
considering equation (2),
x = 7 - 2y (3)
using the value of "x" in (1)
2 (7-2y) - 3y=7
14 - 4y- 3y = 7
14 - 7y = 7
7y = 14 - 7
7y = 7
y = 1 (4)
substituting this value of "y" in (3)
x = 7- 2(1)
x = 5
Step-by-step explanation:
Helo
your answer refer to the attachment
Answer:
see below
Step-by-step explanation:
The point-slope form of the equation of a line is ...
y -h = m(x -k)
for a line with slope m through point (h, k).
Comparing this to the given equation, you see that ...
h = -2, m = 1, k = -4
The line has a slope of 1 and goes through the point (-4, -2). This information is useful for graphing.
__
You can also rearrange the equation to slope-intercept form by subtracting 2 from both sides.
y = x +2
This has a slope of 1 and crosses the y-axis at y=2. It graphs the same as the above.
Note: Consider we need to find the vertices of the triangle A'B'C'
Given:
Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.
Triangle A,B,C with vertices at A(-3, 6), B(2, 9), and C(1, 1).
To find:
The vertices of the triangle A'B'C'.
Solution:
If triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C', then
![(x,y)\to (y,-x)](https://tex.z-dn.net/?f=%28x%2Cy%29%5Cto%20%28y%2C-x%29)
Using this rule, we get
![A(-3,6)\to A'(6,3)](https://tex.z-dn.net/?f=A%28-3%2C6%29%5Cto%20A%27%286%2C3%29)
![B(2,9)\to B'(9,-2)](https://tex.z-dn.net/?f=B%282%2C9%29%5Cto%20B%27%289%2C-2%29)
![C(1,1)\to C'(1,-1)](https://tex.z-dn.net/?f=C%281%2C1%29%5Cto%20C%27%281%2C-1%29)
Therefore, the vertices of A'B'C' are A'(6,3), B'(9,-2) and C'(1,-1).
Answer:
725/50= 14.5
14.5 hours is your answer
i think