Ask question

Ask question

All categories

3 years ago

7

A 4-kg cat is resting on a bookshelf that is 3m high. What is the cats gravitational potential energy relative to the floor if t

he acceleration due to gravity is 9.8m/s squared

1 answer:

Kobotan [32]3 years ago

8 0

Potential energy = mass x gravity x height

P.E = 4 x 9.8 x 3
P.E = 117.6 J

You might be interested in

A wooden cube with the mass of 1kg is placed on a frictionless plane that makes an angle of 30° with the floor.

Anni [7]

Answer:

I dont know

Explanation:

8 0

2 years ago

A cart with a mass of 120 kg and a velocity

klasskru [66]

Answer:

dumpster mass

Explanation:

you will need the mass of the dumpster to calculate using conservation of momentum

6 0

2 years ago

Which statement best explains why an object

slavikrds [6]

D, Mercury as a weaker gravitational pull! Due to mercury being farther from the sun and it being a smaller planet it has a weaker pull

4 0

2 years ago

Read 2 more answers

Total charge is uniformly distributed on a spherical surface of radius R. The sphere is centered at the origin and spins around

Flauer [41]

Answer:

c

Explanation:

i have a A in physics

5 0

3 years ago

A 4.79 g bullet moving at 642.3 m/s penetrates a tree trunk to a depth of 4.35 cm. Use work and energy considerations to find th

vladimir1956 [14]

Answer:

Force, $F=2.27\times 10^4\ N$

Explanation:

Given that,

Mass of the bullet, m = 4.79 g = 0.00479 kg

Initial speed of the bullet, u = 642.3 m/s

Distance, d = 4.35 cm = 0.0435 m

To find,

The magnitude of force required to stop the bullet.

Solution,

The work energy theorem states that the work done is equal to the change in its kinetic energy. Its expression is given by :

$F.d=\dfrac{1}{2}m(v^2-u^2)$

Finally, it stops, v = 0

$F.d=-\dfrac{1}{2}m(u^2)$

$F=\dfrac{-mu^2}{2d}$

$F=\dfrac{-0.00479\times (642.3)^2}{2\times 0.0435}$

F = -22713.92 N

$F=2.27\times 10^4\ N$

So, the magnitude of the force that stops the bullet is $2.27\times 10^4\ N$

7 0

2 years ago