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DaniilM [7]
2 years ago
11

Robert pushes the box to the left at constant speed. In doing so, Robert does ______ work on the box. A. positive B. negative C.

zero
Physics
1 answer:
andrew-mc [135]2 years ago
5 0

Answer:

He does postive work

Explanation:

Because W= F xS sinစ

So since work is done such that Force and distance have the Sam direction

Thus စ=0

Then work is positive in value

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A cheetah can accelerate at 4.5 m/s from rest to a speed of 30.0 m/s. Calculatethe distance
anzhelika [568]

Answer:

d= 100m

Explanation:

Cheetah kinematic

The cheetah moves with uniformly accelerated movement, and the formulas that describe this movement are:

d= v₀*t + (1/2)*a*t²  Formula (1)

vf²=v₀²+2*a*d Formula (2)

vf=v₀+a*t  Formula (3)

Where:

d:distance in meters (m)  

v₀: initial speed in m/s  

vf: final speed in m/s  

a: acceleration in m/s²  

t: time in seconds (s)

Known Data

v₀ =0

a =  4.5 m/s²

vf= 30 m/s.

Problem development

We apply the formula (2) that has known data to calculate the distance :

vf²=v₀²+2*a*d

(30)²= 0 + 2*  4.5* d

d= \frac{900}{9}

d= 100m

8 0
3 years ago
g You want to make simultaneous measurements of the position and momentum of an electron and a proton that are moving along a st
Maslowich

Answer:

1832

Explanation:

From;

Δp Δx = h/4π

Δp = uncertainty in momentum

Δx = uncertainty in position

h= Plank's constant

But p =mv hence, Δp= Δmv

m= mass, v= velocity

mass of electron = 9.11 * 10^-31 Kg

Mass of proton = 1.67 * 10^-27 Kg

since m is a constant,

Δv = h/Δxm4π

For proton;

Δv = 6.6 * 10^-34/4 * 3.14 * 1.67 * 10^-27 * 1 * 10^-10

Δv = 315 ms-1

For electron;

Δv = 6.6 * 10^-34/4 * 3.14 * 9.11 * 10^-31 * 1 * 10^-10

Δv = 577000 ms-1

Ratio of uncertainty of electron to that of proton = 577000 ms-1/315 ms-1= 1832

7 0
2 years ago
An object with a kinetic energy of 2160J has a mass of 120kg. What is the velocity
luda_lava [24]
Hmmm the only formula i know is v = d * t  or volocity = distance * time
5 0
3 years ago
Speed is what type of value?
kondor19780726 [428]

Answer:

Speed can be thought of as the rate at which an object covers distance.

Explanation:

4 0
2 years ago
two horses on opposite sides of a narrow stream are pulling a barge along the stream. Each horse pulls with a force of 720N. The
Setler [38]
Each horse's force forms a right angle triangle with the barge and subtends an angle of 60/2 = 30°. The resultant in the direction of the barge's motion is:
Fx = Fcos(∅)
We can multiply this by 2 to find the resultant of both horses.
Fx = 2Fcos(∅)
Fx = 2 x 720cos(30)
Fx = 1247 N
3 0
3 years ago
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