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sdas [7]
3 years ago
6

In which situation will the lowest resistance occur?

Physics
2 answers:
insens350 [35]3 years ago
8 0

Answer:

thick wire and cold temperatures

Lena [83]3 years ago
6 0

Answer: There may be two types of resistances here:

Air resistance: for example when something is falling down, the air will push the object upwards. As a bigger surface has the object, more air is pushing, so if you want to reduce the resistance yo must reduce the surface area. For example, a sheet of paper will experience more resistance if it is open if you make a small ball with it.

Electric resistance: This is the resistance of conductors against the electrons that try to travel along with it.

there are two equations here.

R = p*L/A, this talks about the volume and density of the conductor, where p is the density, L is the length and A is the area perpendicular to the direction in which the electricity flows.

Then if you reduce the length, and increase the area, the resistance will be reduced.

the other equation is: R(T) = R0( 1 + a*(T - 20°))

Where R0 is the resistance at 20° and a is a coefficient for T = 20°.

Here, you can see that at smaller temperatures, the resistance decreases, so we can conclude that we must increase the area, and decrease the length and temperature.

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Two​ vehicles, a car and a​ truck, leave an intersection at the same time. the car heads east at an average speed of 50 miles pe
olya-2409 [2.1K]

The car heads east at an average speed of 50 miles per​ hour from the intersection point towards East. The truck heads east at an average speed of 60 miles per​ hour from the intersection point towards South.

The distance of car from the intersection point after t hours is 50t.

The distance of truck from the intersection point after t hours is 60t.

Since these distances are perpendicular to each other, distance apart d​ (in miles) at the end of t hours is

d=\sqrt{(50t)^2+(60t)^2} \\ d=10\sqrt{61} t\\ d=78.1t

Thus the distance apart is d=78.1t \;miles

5 0
3 years ago
The position of a particle is given by ~r(t) = (3.0 t2 ˆi + 5.0 ˆj j 6.0 t kˆ) m
Julli [10]

Answer:

v=(6ti+6k)\ m/s

Explanation:

Given that,

The position of a particle is given by :

r(t) = (3.0 t^2 i + 5.0j+ 6.0 tk) m

Let us assume we need to find its velocity.

We know that,

v=\dfrac{dr}{dt}\\\\=\dfrac{d}{dt}(3.0 t^2 i + 5.0j+ 6.0 tk) \\\\=(6ti+6k)\ m/s

So, the velocity of the particle is (6ti+6k)\ m/s.

5 0
3 years ago
A block with mass M = 3 kg is moving on a flat surface with constant speed v1 =
Alchen [17]

Answer:

this makes no since so i cant help you here sorry

5 0
1 year ago
Exercise will not help maintain the health of your endocrine system.
Mashcka [7]
A. True

Hope this helps :)
6 0
2 years ago
A cake is removed from a 350◦F oven and placed on a cooling rack in a 70◦F room. After 30 minutes the cake is 200◦F. When will i
galben [10]

Answer:

350 F to 100 F it take approx 87.33 min  

Explanation:

given data

oven = 350◦F

cooling rack = 70◦F

time = 30 min

cake = 200◦F

solution

we apply here Newtons law of cooling  

\frac{dT}{dt} = -k(T-Ta)

\frac{dy}{dt} = \frac{d}{dt} (T(t) -Ta)

= \frac{dT}{dt} -\frac{dTa}{dt} =\frac{dT}{dt} = -k(T-Ta)

-ky \frac{dy}{dt} = -ky

T(t) -Ta = (To -Ta) e^{-kt} T(t) = Ta+ (To -Ta)  e^{-kt}

put her value for time 30 min and T(t) = 200◦F and To =350◦F  and Ta = 70◦F

so here

200 = 70 + ( 350 - 70 ) e^{-k30}

k = 0.025575

so here for  T(t) = 100F

100 = 70 + ( 350 - 70 ) e^{-0.025575*t}

time = 87.33 min

so here 350 F to 100 F it take approx 87.33 min  

5 0
3 years ago
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