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likoan [24]
3 years ago
10

_____states that the physical and chemical properties of the elements are periodic within the sequence of their atomic numbers.

Chemistry
2 answers:
Brums [2.3K]3 years ago
8 0
It would be Periodic im almost one hundred percent sure about it
Novay_Z [31]3 years ago
4 0
The answer is Periodic
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This reaction is sometimes used to inflate life rafts, weather balloons, and the like, where a simple, compact means of generati
tia_tia [17]

Answer: 10.2 grams

Explanation:

The balanced chemical reaction is :

CaH_2(s)+2H_2O(l)\rightarrow Ca(OH)_2(aq)+2H_2(g)

According to the ideal gas equation:

PV=nRT

P = Pressure of the gas = 740 torr =  0.97 atm    (760torr=1atm)

V= Volume of the gas = 12.0 L

T= Temperature of the gas = 19°C = 292 K    0^0C=273K

R= Gas constant = 0.0821 atmL/K mol

n= moles of gas

n=\frac{PV}{RT}=\frac{0.97\times 12.0}{0.0821\times 292}

n=0.48

According to stoichiometry:

2 moles of hydrogen are generated by = 1 mole of CaH_2

Thus 0.48 moles of hydrogen are generated by =\frac{1}{2}\times 0.48=0.24 moles of CaH_2

Mass of  CaH_2=moles\times {\text {Molar mass}}=0.24mol\times 42g/mol=10.2g

Thus 10.2 grams of CaH_2 are needed to generate 12.0 L of hydrogen gas if the pressure of hydrogen is 740. torr at 19°C

5 0
3 years ago
A 28.5 gram piece of iron is added to a graduated cylinder containing 45.5 mL of water. The water in the cylinder rises to the 4
yan [13]

7.91 g/ml is the density of the iron piece of 28.5 gms.

Explanation:

The density of a substance is defined as the volume it occupies.  It tells the matter present in a substance.

The density is mass per unit volume and is denoted by p.

The formula for density is given by:

density (p) = \frac{mass}{volume}

Data given is :

mass= 28.5 grams

V1 = 45.5 ml

V2= 49.1 ml

The initial volume of water was 45.5 ml, when iron piece of 28.5 grams was added the final volume was 49.1 ml.

Putting the values in the equation of density

p = \frac{28.5}{49.1-45.5}

p = 7.91 g/ml

Since iron is a dense material it will occupy less volume

4 0
3 years ago
There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In
KIM [24]

Answer:

ΔH = -470.4kJ

Explanation:

It is possible to sum 2 or more reactions to obtain the ΔH of the reaction you want to study (Hess's law). Using the reactions:

1. CaC2(s) + 2H2O(l) → C2H2(g) + Ca(OH)2(s)ΔH = −414kJ

2. 6C2H2(g) + 3CO2(g) + 4H2O(g) → 5CH2CHCO2H(g)ΔH = 132kJ

6 times the reaction 1.

6CaC2(s) + 12H2O(l) → 6C2H2(g) + 6Ca(OH)2(s)ΔH = −414kJ*6 = -2484kJ

This reaction + 2:

6CaC2(s) + 3CO2(g) + 16H2O(l) →  + 6Ca(OH)2(s) + 5CH2CHCO2H(g) ΔH = -2484kJ + 132kJ = -2352kJ

As we want to calculate the net change enthalpy in the formation of just 1 mole of acrylic acid we need to divide this last reaction in 5:

6/5CaC2(s) + 3/5CO2(g) + 16/5H2O(l) →  + 6/5Ca(OH)2(s) + CH2CHCO2H(g) ΔH = -2352kJ / 5

<h3>ΔH = -470.4kJ</h3>

4 0
3 years ago
Incomplete dash of fuels produces many poisonous dash​
tangare [24]

Answer:

Incomplete combustion of fuels produces a very poisonous gas called carbon monoxide:Excessive inhaling of carbon dioxide gas can kill a person.

I don't know if this is correct, your question did not have much context.

6 0
3 years ago
How does the density of a gas depend on the molar mass of the gas?
AlladinOne [14]

Answer:

The density of the ideal gas is directly proportional to its molar mass.

Explanation:

Density is a scalar quantity that is denoted by the symbol ρ (rho). It is defined as the ratio of the mass (m) of the given sample and the total volume (V) of the sample.

\rho = \frac{m}{V}                          ......equation (1)

According to the ideal gas law for ideal gas:

PV = nRT                                       ......equation (2)

Here, V is the volume of gas, P is the pressure of gas, T is the absolute temperature, R is Gas constant and n is the number of moles of gas

As we know,

The number of moles: n = \frac{m}{M}

where m is the given mass of gas and M is the molar mass of the gas

So equation (2) can be written as:

PV = \frac{m}{M}RT

⇒ PM= \frac{m}{V} RT

⇒ \frac{PM}{RT}= \frac{m}{V}             ......equation (3)

Now from equation (1) and (3), we get

\frac{PM}{RT}= \frac{m}{V} = \rho  

⇒ Density of an ideal gas: \rho = \frac{PM}{RT}  

⇒ <em>Density of an ideal gas: ρ ∝ molar mass of gas: M</em>

<u>Therefore, the density of the ideal gas is directly proportional to its molar mass. </u>

6 0
3 years ago
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