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aev [14]
3 years ago
11

A 265 ml flask contains pure helium at a pressure of 749 torr. A 455 ml flask contains pure argon at a pressure of 729 torr. The

two flasks are connected through stopcock and are at the same temperature. What is the pressure once the stopcock is opened?
a. 736 Torr
b. 276 Torr
c. 461 Torr
d. 250 Torr
e. 449 Torr
Chemistry
1 answer:
Doss [256]3 years ago
6 0

Answer:

a. P_T=736.4torr

Explanation:

Hello,

By using Boyle's law, one computed the final pressure for both helium and argon as shown below:

P_{2,He}=\frac{265mL*749torr}{265mL+455mL} =275.67torr\\P_{2,Ar}=\frac{455mL*729torr}{265mL+455mL} =460.69torr\\

Now, by adding the resulting pressures, we compute the final pressure after the stopcock is opened:

P_T=P_{2,He}+P_{2,Ar}=275.67torr+460.69torr\\P_T=736.4torr

So the answer is a.

Best regards.

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Answer:

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Explanation:

Electrons are conserved in a chemical equation.

The superscript of \rm Ag^{1+} indicates that each of these ions carries a charge of +1. That corresponds to the shortage of one electron for each \rm Ag^{+} ion.

Similarly, the superscript +3 on each \rm Al^{3+} ion indicates a shortage of three electrons per such ion.

Assume that the coefficient of \rm Ag^{+} (among the reactants) is x, and that the coefficient of \rm Al^{3+} (among the reactants) is y.

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