Answer: the maximum heigth of the stadium at ist back wall is 151.32 ft
Explanation:
1. use the position (x) equation in parobolic movement to find the time (t)
565 ft = [frac{176 ft}{1 s\\}[/tex] * cos (35°) * t
t= 3.92 s
2. use the position (y) equation in parabolic movement to find de maximun heigth the ball reaches at 565 ft from the home plate.
y= [[frac{176 ft}{1 s\\}[/tex] * sen (35°) * 3.92 s] - 
y= 148.32 ft
3. finally add the 3 ft that exist between the home plate and the ball
148.32 ft + 3 ft = 151.32
Answer: 2.22s
Explanation: wave speed = 450 m/s, A = amplitude = 1.6mm, λ= wavelength = 0.19m
Wave speed = distance traveled / time taken
Distance traveled = 1km = 1000 m
450 = 1000/ t
t = 1000/ 450 = 2.22s
The answer is 25.37 hope this helps