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2 years ago

How do you put 0.0015kg in scientific notation

Physics

1 answer:

Anna11 [10]2 years ago

4 0

0.0015 kg would be 1.5*10^-2 kg in scientific notation

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Will give correct answer brainliest 5 kg m/s 8kg m/s 80 kg m/s 200 kg m/s

o-na [289]

Answer: Here this will help you..

Explanation:

1 kg-m/s to kilogram-force meter/second = 1 kilogram-force meter/second

5 kg-m/s to kilogram-force meter/second = 5 kilogram-force meter/second

10 kg-m/s to kilogram-force meter/second = 10 kilogram-force meter/second

20 kg-m/s to kilogram-force meter/second = 20 kilogram-force meter/second

30 kg-m/s to kilogram-force meter/second = 30 kilogram-force meter/second

40 kg-m/s to kilogram-force meter/second = 40 kilogram-force meter/second

50 kg-m/s to kilogram-force meter/second = 50 kilogram-force meter/second

75 kg-m/s to kilogram-force meter/second = 75 kilogram-force meter/second

100 kg-m/s to kilogram-force meter/second = 100 kilogram-force meter/second

8 0

1 year ago

A 50 N object is on Earth. What is its mass?

faust18 [17]

Answer: 5.10 KG

Explanation: W = 50 N

BY FORMULA

W = MG

M = W/G

M = 50 /9.8

M= 5.10 KG

7 0

1 year ago

A golf ball (m = 59.2 g) is struck a blow that makes an angle of 50.5 ◦ with the horizontal. The drive lands 130 m away on a fla

fomenos

Answer:

The force is calculated as 338.66 N

Explanation:

We know that force is given by

$\overrightarrow{F}=\frac{d\overrightarrow{p}}{dt}=\frac{m(v_{f}-v_{o})}{\Delta t}$

We know that range of a projectile is given by

$R=\frac{v_{o}^{2}sin(2\theta )}{g}$

it is given that R=130 m applying values in the above equation we get

$R=\frac{v_{o}^{2}sin(2\theta )}{g}\\\\v_{0}=\sqrt{\frac{Rg}{sin(2\theta )}}\\\\\therefore v_{o}=\sqrt{\frac{130\times 9.81}{sin(2\times 50.5_{o}} )}\\\\v_{o}=36.04m/s$

Thus the force is obtained as

$\overrightarrow{F}=\frac{d\overrightarrow{p}}{dt}=\frac{59.2\times 10^{}-3(36.04-0)}{6.3\times 10^{-3}}$

Thus force equals $F=338.66N$

4 0

2 years ago

Read 2 more answers

A waterbed has a force of 1300N on the floor. It exerts 347 Pa of pressure. What is the area of the waterbed?

Sergio [31]

Answer:

Pressure = Force/Area

347 = 1300/Area

Area = 1300/347

area= 3.47m2

6 0

2 years ago

Read 2 more answers

You have a summer job working at a company developing systems to safely lower large loads down ramps. Your team is investigating

sweet-ann [11.9K]

Answer:

Explanation:

find the solution below

3 0

2 years ago