The value of spring constant and the oscillator's damping constant is
K= 6605.667008, b= 0.002884387
Explanation:
For Weakly damping spring oscillator
K/m = W_0^2 (at resonance)
K= mW_0^2
=0.206 * ( 2π * 28.5) ^2
=0.206 * (2π)^2 * (28.5)^2
K= 6605.667008
F = - bV
b= -F/V = -F/ -W_0 * m
=F/W_0 * m
= 0.438N / 2π * 28.5 * 0.848
b= 0.002884387
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Answer:
(A) 
Explanation:
Given:
Charge of one particle (q₁) = -0.0050 C
Charge of another particle (q₂) = 0.0050 C
Separation between them (d) = 0.025 m
We know that, from Coulomb's law, electric force acting between two charged particles is given as:
Plug in the given values and solve for electric force, 
. This gives,
Therefore, option (A) is correct. Negative sign implies that the nature of electric force is attraction.
