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Gennadij [26K]
3 years ago
6

A hockey player uses her hockey stick to exert a force of 6.81 N on a stationary hockey puck. The hockey puck has a mass of 165

g. What is the acceleration of the hockey puck?
a. 0.13 m/s2

b. 11.3 m/s2

c. 21.3 m/s2

d. 31.3 m/s2

e. 41.3 m/s2
Physics
1 answer:
Anna007 [38]3 years ago
5 0

Answer:

41.3 m/s^2 option (e)

Explanation:

force, F = 6.81 N

mass, m = 165 g = 0.165 kg

Let a be the acceleration of the puck.

Use newtons' second law

Force = mass x acceleration

6.81 = 0.165 x a

a = 41.27 m/s^2

a = 41.3 m/s^2

Thus, the acceleration of the puck is 41.3 m/s^2.

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At 3.00 m from a source that is emitting sound uniformly in all directions, the sound level (b) is 60.0 dB.
grigory [225]

Given that,

At 3.00 m from a source that is emitting sound uniformly in all directions, the sound level is 60.0 dB.

To find,

The distance from the source would the sound level be one-fourth the sound level at 3.00 m.

Solution,

The intensity from a source is inversely proportional to the distance.

Let I₁ = 60 dB, r₁ = 3 m, I₂ = 60/4 = 15 dB, r₂ =?

Using relation :

\dfrac{I_1}{I_2}=\dfrac{r_2^2}{r_1^2}\\\\r_2^2=\dfrac{I_1r_1^2}{I_2}\\\\r_2^2=\dfrac{60\times (3)^2}{15}\\\\r_2=6\ m

So, at a distance of 6 m the sound level will be one fourth of the sound level at 3 m.

8 0
2 years ago
A young 34-kg ice hockey goalie, originally at rest, catches a 0.145-kg hockey puck slapped at him at a speed of 34.5 m/s. In th
irinina [24]

The concept that we need to give solution to this problem is collision equation given by momentum conservation,

Our values are,

m_2 = 0.145 kg\\u_2 = 34.5 m/s\\m_1 = 34 kg\\u_1 = 0

Then,

Part A) We can here note that the velocity for the puck is zero (there is not a velocity in that direction)

V_{goalie} = \frac{m_1-m_2}{m_1+m_2}V_{01} + \frac{2m_2}{m_1+m_2}V_{02}

V_{goalie} = \frac{34-0.145}{34+0.145}(0)+\frac{2*0.145}{34+0.145}(34.5)

V_{goalie} = 0.2930m/s

Part B ) We apply the same solution but know we note that in the collision for the Goalie the velocity is zero.

V_{puck} = \frac{m_1-m_2}{m_1+m_2}V_{02} + \frac{2m_2}{m_1+m_2}V_{01}

V_{puck} = \frac{34-0.145}{34+0.145}(34.5)+\frac{2*0.145}{34+0.145}(0)

V_{puck} = 34.20m/s

7 0
3 years ago
Both hydrogen gas and helium gas are lighter than air. Why is helium used to lift blimps instead of hydrogen?
neonofarm [45]
A because helium is in balloons and it’s lifting the balloon. Hope this helps!
4 0
3 years ago
Please help !!
ExtremeBDS [4]

Answer:

Just as the angles of the sun, moon and Earth affect tidal heights over the course of a lunar month, so do their distances to one another. Because the moon follows an elliptical path around the Earth, the distance between them varies by about 31,000 miles over the course of a month.

Hope this helped, have a nice rest of your day!

3 0
3 years ago
The density of a substance is its mass per unit volume. 
Over [174]

Answers:

a) kg/m^{3}

b) derived

Explanation:

Density D is a characteristic property of substances and materials and is defined as the relationship between the mass m and volume V of a specific substance or material, as shown below:

D=\frac{m}{V}

This means density is inversely proportional to volume.

In addition, density is a derived unit, because is based on two basic units of the International Sistem of Units: Mass (kilograms) and Volume (cubic meters)

7 0
2 years ago
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