a) The velocity of the boat relative to the shore is 3.40 m/s and b) The position of the boat relative to its point of origin after 3s is 10.20m.
Here it is given that the speed of the boat (x) = 2.20m/s
The speed of the stream current (y) = 1.20m/s
a) We have to find the velocity of the boat relative to the shore.
The speed of the boat = x + y
= 2.20 + 1.20
= 3.40m/s
b) Now we have to find the position of the boat after 3s
The formula for speed:
Speed = Distance/ Time
distance = speed × time
speed = 3.40m/s
Time = 3s
distance = 3.40 × 3
= 10.20 m
Therefore we get a) speed as 3.40m/s and b) distance as 10.20m.
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The light reactions could be viewed as analogous to a hydroelectric dam. In that case, the wall of the dam that holds back the water would be analogous to the thylakoid membrane.
Thylakoid membrane is present in cyanobacteria and chloroplasts of plants. It plays a crucial role in photosynthesis and photosystem II reactions.
In general, these are the regions where light-dependent reactions take place. The thylakoid membrane is a lipid-bound membrane that maintains potential difference and also controls the flow of liquids across the membrane during light reactions.
In the provided case, we can see that the wall of the dam holds back the water, similarly, in light-dependent reactions, thylakoid membranes control the liquid flow and also regulate the potential gradient across the membrane and also allow the selective proteins to pass through.
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That's true.
I have a hunch that there definitely IS a change of phase at every reflection.
Answer:
Drawing the triangle:
H / x = tan 52.2 = 1.29
H / (4.6 - x) = tan 28.8 = .550
H = 1.29 x
H = .55 * 4.6 - .55 x
1.84 x = 2.53 combining equations
x = 1.38
4.6 - 1.38 = 3.22
Total base of triangle = 1.38 + 3.22 = 4.6
H / x = tan 52,2 = 1.29
H = 1.29 * 1.38 = 1.78 height of triangle
Check:
1.78 / 3.22 = tan 28.9
This agrees with the given value of 28.8
