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2 years ago

What features of your design helped your rocket hit the target?

Physics

1 answer:

jonny [76]2 years ago

8 0

Answer:

What features of your design helped your rocket hit the target? (Key factors include the rocket's weight, launch angle, ability to fly straight, and the balloon's pressure.) After testing, what changes did you make to your rocket and launcher? (Answers will vary.)

Explanation:

PLEASE GIVE ME BRAINLIEST IF NEW YOULL SEE NEAR MY ANSWER MARK AS BRAINLIEST IF NOT YOULL HAVE TO WAIT A DAY AND BRAINLY WILL REMIND YOU

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Four wires meet at a junction. In two of the wires, currents and enter the junction. In one of the wires, current leaves the jun

Vera_Pavlovna [14]

Answer:

Explanation:

Kirchoff's current law: It states that the total current entering at a junction is equal to the total current leaving at the junction. It isbased on conservation of charge.

As two current i1 and i2 is entering at the junction and i3 is leaving, so the current in forth wire is

i4 = i1 + i2 - i3

4 0

2 years ago

Help me solve this please

Leto [7]

Since it's a projectile being launched the only force acting upon it is gravity, since the object is in free fall once it's launched

so to calculate time you'd utilize the general formula of
$xf = xi + vxi(t) + \frac{1}{2} (a) {t}^{2}$
and then solve using time and make it into the y axis, so change the x's to y's, which will change a to g.
since Vyi is always usually 0, you can drop that out of this equation so the formula to find time would be
$t = \sqrt{ \frac{2(y)}{g} }$
So you'll plug in and it'll be
$t = \sqrt{ \frac{2( - 49m)}{ - 9.81 \frac{m}{s {}^{2} } } }$
to find the maximum height you'll have to do some trigonometry to solve it.
To make it easier draw a triangle
put the 60° mark as shown in the picture.
Then you'll need to find the hypotenuse or horizontal to find the vertical
So the hypotenuse would be the 113m/s
so then you'll use
$\ \sin( 60) = ( \frac{o}{h})$

plug in the numbers
$113( \ \sin (60) ) = o$
now that you have the vertical

use the formula
${vf}^{2} = {vi}^{2} + 2gd$
solve for d which will give you the hypotenuse
$d = { (-vertical \frac{m}{s} )}^{2} \div 2( - 9.81 \frac{m}{ {s}^{2} } )$
The "vertical" is what you found in the previous step.
Vf^2 is equal to 0 so you can just drop that number out since it's 0
then once you have that then youre not done yet
since you're on a cliff of 49 m you'll have to add 49m to the previous answer that you found d to find the maximum height.

I hope this helps!

6 0

2 years ago

The national high magnetic field laboratory holds the world record for creating the strongest magnetic field. for brief periods

max2010maxim [7]

Newton’s 2nd law states that Force is equal to the product of mass (m) and acceleration (a):

F = m a ---> 1

While in magnetic forces, force can also be expressed as:

F = q v B ---> 2

where,

q = total charge

v = velocity = 45 cm / s = 0.45 m / s

B = the magnetic field = 85 T

First we solve for the total charge, q:

q = 3.8 × 10^-23 g (1 mol / 23 g) (6.022 × 10^23 electrons / mol) (1.602 × 10^-19 C / electron)

q = 1.594 × 10^-19 C

We equate equations 1 and 2 then solve for acceleration a:

m a = q v B

a = q v B / m

a = [1.594 × 10^-19 C * 0.45 m / s * 85 T] / 3.8 × 10-26 kg

a = 160,437,862.2 m/s^2

Therefore the maximum acceleration of Na ions is about 160 × 10^6 m/s^2.

5 0

3 years ago

Read 2 more answers

Plz help I’ll give Brainliest

Mariana [72]

Answer:

Explanation:

5 0

2 years ago

Read 2 more answers

Of the following, which generally causes the greatest damage?

maksim [4K]

I guess it is a: seismic waves

3 0

3 years ago