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MatroZZZ [7]
3 years ago
8

How many orbitals are there in the third shell (n=3)?

Chemistry
2 answers:
andrezito [222]3 years ago
5 0
The third shell contanis one s orbital,three p orbitals and five d orbitals.Each orbital hold 2 electron so the total number of electron which can be accommodate in third shell are 18 electrons
Dmitrij [34]3 years ago
4 0

Answer:

9

Explanation:

Hello,

In this case, since the third shell of electrons has  the following 3 subshells:

3s, 3p \ and \  3d

- The s subsehll has one orbital for one pair of electrons: s^1 \ and \   s^2.

- The p subsehll has three orbitals for three pairs of electrons: p^1, \ p^2,\ p^3, \ p^4,\ p^5\ and \ p^6\.

- The d subsehll has five orbital for five pairs of electrons d^1, \ d^2,\ d^3, \ d^4,\ d^5,\ d^6,\ d^7,\ d^8,\   d^9\ and \ d^{10}\.

Therefore, the total number of orbitals when n=3 is:

1+3+5=9

Best regards.

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How many moles of methane (CH4) could be made from 4.6 moles of hydrogen?
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Number of moles of methane form = 2.3 mol

Explanation:

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                     H₂              :           CH₄

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What is the number of moles in 3.0 X 10^24 atoms of Carbon
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4 0
1 year ago
what is the balanced equation for the reaction of solid magnesium metal with oxygen gas to produce solid magnesium oxide
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Answer:

2Mg + O₂ ⟶ 2MgO

Explanation:

Step 1. Start with the most complicated-looking formula (O₂?).

Put a 1 in front of it.

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Step 2. Balance O.

We have fixed 2 O on the left. We need 2O on the right. Put a 2 in front of MgO.

Mg + 1O₂ ⟶ 2MgO

Step 3. Balance Mg.

We have fixed 2 Mg on the right-hand side. We need 2 Mg atoms on the left. Put a 2 in front of Mg.

2Mg + 1O₂ ⟶ 2MgO

Every formula now has a coefficient. The equation should be balanced. Let’s check.

<u>Atom</u>  <u>On the left</u>  <u>On the righ</u>t

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  O                2                  2

All atoms are balanced.

The balanced equation is

2Mg + O₂ ⟶ 2MgO

4 0
3 years ago
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