Answer:
equivalence ratio= 0.08333
Explanation:
The balanced stoichoimetric equation tells us the amount of hydrogen in moles required to react with a specific amount of oxygen in moles to produce water. The Balanced equation of the reaction is shown
2H_{2}+O_{2} → 2 H_{2}O
this means 2 parts of Hydrogen will react with one part of oxgen to produce 2parts of water as shown above
in the question, 1 part of hydrogen was made to react with 6parts of oxygen. which means comparing with the balanced equation, oxygen is in excess as only \frac{1}{2} part of oxygen will react with 1part of hydrogen. the equation is shown below
1H_{2}+\frac{1}{2} O_{2} → 1 H_{2}O +\frac{11}{2}O_{2}
The equivalence ratio is the ratio of actual fuel to air ratio to stoichiometric fuel to air ratio and is calculated as follows:
actual fuel/air ratio = parts of fuel/parts of air
=\frac{1}{6}
stoichiometric fuel/air ratio = \frac{2}{1}
equivalence ratio = \frac{actual fuel/air ratio}{stoichiometric fuel/air ratio }
=\frac{\frac{1}{6} }{\frac{2}{1} }
= 0.08333
Have a great day Jershaun9358
