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fgiga [73]
3 years ago
9

The fifth and tenth term of an A.P are 8 and -7 respectively .Find the 100th and 500th term of the A.P

Mathematics
1 answer:
Klio2033 [76]3 years ago
8 0
An arithmetic sequence can be expressed as:

a(n)=a+d(n-1), where a(n) is the value of the nth term, a is the initial term, d is the common difference, and n is the term number....we are given to terms...

8=a+d(5-1) and -7=a+d(10-1) so

8=a+4d and -7=a+9d

So if we get the difference of these two equations we have:

15=-5d, so d=-3

We again use one of the original equations to solve for the first term and using the common difference d that we just found...

8=a-3(5-1)

8=a-12, so a=20, so are sequence has the rule:

a(n)=20-3(n-1) or more neatly:

a(n)=23-3n so

a(100)=-277

a(500)=-1477
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Step-by-step explanation:

Given:-

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                         u = 67.2

                         s.d = 4.6

- The random variable (X) that denotes standardized test scores following normal distribution:

                         X~ N ( 67.2 , 4.6^2 )

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What percent of the data fell between 62.6 and 71.8?

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                          P ( 62.6 < X < 71.8 )

                          P ( (62.6 - 67.2) / 4.6 < Z < (71.8 - 67.2) / 4.6 )

                          P ( -1 < Z < 1 )

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                          P ( -1 < Z < 1 ) = 68%

                          P ( -2 < Z < 2 ) = 95%

                          P ( -3 < Z < 3 ) = 99.7%

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