Answer:
Molarity of stock HCl solution is 0.89 M
Explanation:
The given problem can be solved using laws of dilution.
According to laws of dilution- ![C_{1}V_{1}=C_{2}V_{2}](https://tex.z-dn.net/?f=C_%7B1%7DV_%7B1%7D%3DC_%7B2%7DV_%7B2%7D)
Where,
and
are initial and final concentration of a solution
and
are initial and final volume of a solution
Here,
,
and ![V_{2}=500mL](https://tex.z-dn.net/?f=V_%7B2%7D%3D500mL)
So,
=
= 0.89 M
Hence, molarity of stock HCl solution is 0.89 M
H₂ is the limiting reactant.
<u>Explanation:</u>
H₂ reacts with O₂
The reaction would be
2H₂ + O₂ → 2H₂O
According to the balanced equation, 2 moles of H₂ reacts with 1 mole of O₂ to form 2 moles of H₂O.
The ratio of usage of H₂ and O₂ is 2 : 1 respectively
If 3 moles of H₂ and 2 moles of O₂ are present then:
3 moles of H₂ would require 1.5 moles of O₂ ( 2 : 1 of H₂ and O₂ )
Out of 2 moles of O₂, 1.5 moles would be used and 0.5 mole would be in excess.
Therefore, H₂ is the limiting reactant as the number of moles of H₂ are not enough to use all the O₂.
She should leave 6.41 because 42.76 x 15%