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Fed [463]
4 years ago
6

All the gold ever mined would fit into a single cube about how many feet on a side

Mathematics
1 answer:
bezimeni [28]4 years ago
8 0
<span>All the gold ever mined would fit into a single cube about 60 feet on a side.
</span>
A figure that is widely used by investors comes from Thomson Reuters GFMS, which produces an annual gold survey.

Their latest figure for all the gold in the world is 171,300 tonnes.

A cube made of 171,300 tonnes would be about 20.7m (68ft) on each side.

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What is the smallest integer that can be added to -2m3 − m + m2 + 1 to make it completely divisible by m + 1
tia_tia [17]
When divided by 2 we get perfect square 
<span>(2^n * 3^m) / 2 = 2^(n-1) * 3^m is a perfect square </span>
(n-1) and m are divisible by 2
 <span>When divided by 3 we get perfect cube </span>
<span>(2^n * 3^m) / 3 = 2^n * 3^(m-1) is a perfect cube </span>
n and (m-1) are divisible by 3 
<span>(n-1) divisible by 2 & n divisible by 3 → n = 3 </span>
<span>m divisible by 2 & (m-1) divisible by 3 → m = 4 
</span><span>Number = 2³ * 3⁴ = 648 
</span>648/2 = 324 = 18² 
<span>648/3 = 216 = 6³ 
</span>ANSWER: 648
8 0
4 years ago
3. The Lopez Family meets with a financial planner who advises them to save 15%
Naddik [55]

Answer:

1281

Step-by-step explanation:

15% of 8540=1281

3 0
3 years ago
Six pairs of data yield r = 0.444 and the regression equation y = 5x + 2. also, y = 18.3. what is the best predicted value of y
gladu [14]

Answer:

12

Step-by-step explanation:

To find the best predicted value of y, substitute 5 for x in y = 5x + 2.

We get y = 5(5) + 2, or 12.

7 0
3 years ago
A ship traveling east at 45 mph is 15 mi from a harbor when another ship leaves the harbor traveling east at 60 mph. How long do
Harman [31]

Answer:

  1 hour

Step-by-step explanation:

I find these easiest to work by considering the initial difference in distance and the speed at with that gap is closing.

__

The gap is 15 miles, the distance the first ship is from harbor when the second ship starts.

The rate of closure is the difference in the speeds of the two ships:

  60 mph -45 mph = 15 mph

Then the closure time is ...

  time = distance/speed

  time = (15 mi)/(15 mi/h) = 1 h

It will take the second ship 1 hour to catch up to the first ship.

7 0
2 years ago
What are the answers?
IRISSAK [1]
The answer is no answer because there is no pic so 0
7 0
3 years ago
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