Answer:
and 
Explanation:
Our goal for this question is the calculation of the number of moles of the molecules produced by the reaction of hydrazine (
) and <u>oxygen</u> (
). So, we can start with the <u>reaction</u> between these compounds:
Now we can <u>balance the reaction</u>:
In the problem, we have the values for both reagents. Therefore we have to <u>calculate the limiting reagent</u>. Our first step, is to calculate the moles of each compound using the <u>molar masses values</u> (32.04 g/mol for
and 31.99 g/mol for
):


In the balanced reaction we have 1 mol for each reagent (the numbers in front of
and
are 1). Therefore the <u>smallest value would be the limiting reagent</u>, in this case, the limiting reagent is
.
With this in mind, we can calculate the number of moles for each product. In the case of
we have a <u>1:1 molar ratio</u> (1 mol of
is produced by 1 mol of
), so:

We can follow the same logic for the other compound. In the case of
we have a <u>1:2 molar ratio</u> (2 mol of
is produced by 1 mol of
), so:

I hope it helps!
You can start by writing out the molecular formula of each molecule.
Aluminum (Al 3+) Phosphate (PO4 3-)
AlPO4
Nickel II (Ni 2+) sulfide (S 2-)
NiS
Aluminum Sulfide
Al2S3
Nickel Phosphate
Ni3(PO4)2
If you’re wondering, we get those charges by looking at the periodic table. The metals usually have a + charge based on their group number. The nonmetals usually - charge egual to 8 - their group number.
You then balance the ions by flipping the charges, dropping the signs, and adding them in as subscripts.
Now we can put it into an equation
AlPO4 + NiS —-> Al2S3 + Ni3(PO4)2
Balance by adding coefficients
2 AlPO4 + 3 NiS —-> Al2S3 + Ni3(PO4)2
<span> this represents the relative overall energy of each orbital, and the energy of each orbital increases as the distance from the nucleus increases</span>
Answer:
Total number of water molecules produced after the reaction is 1.956×10^22 molecules of water.
Explanation:
By the reaction
H2+ 1/2 O2 → H2O
Moles of O2 = 5.2\32
⇒1 mole of O2 produce 1 mole of H2O
1 mole O2 will produce 2 mole of H2O
Therefore, 5.2\32 mole will produce 
⇒ Molecules of H2O will be
= 
= 1.956×10^22 moleculesof H2O.
Answer:
53.93 g Ag
Explanation:
3.011x1023 atoms Ag x <u> 1 mole Ag </u> x <u>107,8683 grams</u> =
6.022x
atoms 1 mole Ag
use the periodic table fo find Ag atomic mass and use Avogadro´s number