Answer: 9.9 grams
Explanation:
To calculate the moles, we use the equation:
a) moles of 
b) moles of 
According to stoichiometry :
1 mole of combine with 1 mole of
Thus 0.33 mole of will combine with =
mole of
Thus is the limiting reagent as it limits the formation of product.
As 1 mole of give = 1 mole of 
Thus 0.33 moles of give =
of
Mass of 
Thus theoretical yield (g) of produced by the reaction is 9.9 grams
When MgO and H2O react they form Magnesium Hydroxide Mg(OH)2
Answer:
4.867 L of ammonia
Explanation:
Using Haber's process to form ammonia using Nitrogen and hydrogen, the equation is :
N₂ + 3H₂ → 2NH₃
Here, 3 moles of hydrogen gas gives 2 moles of ammonia.
1 mole of any substance occupies 22.4L at STP
So, 3 x 22.4L of hydrogen gives 2 x 22.4 L of ammonia
Then 7.3 L of hydrogen will give:
=
=
= 4.867 L of ammonia
