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3 years ago

What happens to an object at rest if balanced forces act upon it?

1 answer:

4 0

Newton's first law of motion states that an object at rest will remain at rest unless an unbalanced force acts on it. If you apply balanced forces on the object there would be no net force. The body does not accelerate but instead stays at rest.

Another way to look at this problem is to use Newton's second law of motion. The first law states that $F = m\times a$ , where $a$ is the acceleration $F$ is the net force and $m$ is the mass of the object.

When F is zero, the acceleration of the object is zero. This means that if the object had a velocity of zero before the balanced forces started acting, the velocity will stay at zero after the balanced forces begin to act. If the object was moving at a constant velocity before the balanced forces started acting on it, it would continue at that constant velocity after the balanced forces begin to act.

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A 0.100 M solution of bromoacetic acid (BrCH2COOH) is 13.2% ionized. Calculate [H+]? Calculate BrCH2COO^ - ? Calculate BrCH2COOH

Natali [406]

Answer: The concentration of hydrogen ion and bromoacetate ion is 0.0132 M and 0.0132 M resepectively and that of bromoacetic acid is 0.0868 M

Explanation:

We are given:

Molarity of bromoacetic acid = 0.100 M

Percent of ionization = 13.2 %

The chemical equation for the ionization of bromoacetic acid follows:

$BrCH_2COOH\rightarrow BrCH_2COO^-+H^+$

1 mole of bromoacetic acid produces 1 mole of bromoacetate ion and 1 mole of hydrogen ion

Molarity of hydrogen ion = 13.2 % of 0.100 = $\frac{13.2}{100}\times 0.100=0.0132M$

Molarity of bromoacetate ion = molarity of hydrogen ion = 0.0132 M

Molarity of bromoacetic acid = Molarity of solution - Molarity of ionized substance

Molarity of bromoacetic acid = 0.100 - 0.0132 = 0.0868 M

Hence, the concentration of hydrogen ion and bromoacetate ion is 0.0132 M and 0.0132 M resepectively and that of bromoacetic acid is 0.0868 M

8 0

3 years ago

g Suppose 0.0350 g M g is reacted with 10.00 mL of 6 M H C l to produce aqueous magnesium chloride and hydrogen gas. M g ( s ) +

iren2701 [21]

Answer:

Mg will be the limiting reagent.

Explanation:

The balanced reaction is:

Mg + 2 HCl → MgCl₂ + H₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Mg: 1 mole
HCl: 2 moles
MgCl₂: 1 mole
H₂: 1 mole

Being the molar mass of each compound:

Mg: 24.3 g/mole
HCl: 36.45 g/mole
MgCl₂: 95.2 g/mole
H₂: 2 g/mole

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Mg: 1 mole* 24.3 g/mole= 24.3 g
HCl: 2 moles* 36.45 g/mole= 72.9 g
MgCl₂: 1 mole* 95.2 g/mole= 95.2 g
H₂: 1 mole* 2 g/mole= 2 g

0.0350 g of Mg is reacted with 10.00 mL (equal to 0.01 L) of 6 M HCl.

Molarity being the number of moles of solute that are dissolved in a certain volume, expressed as:

$Molarity=\frac{number of moles of solute}{volume}$

in units $\frac{moles}{liter}$

then, the number of moles of HCl that react is:

$6 M=\frac{number of moles of HCl}{0.01 L}$

number of moles of HCl= 6 M*0.01 L

number of moles of HCl= 0.06 moles

Then you can apply the following rule of three: if by stoichiometry 2 moles of HCl react with 24.3 grams of Mg, 0.06 moles of HCl react with how much mass of Mg?

$mass of Mg=\frac{0.06 moles of HCl* 24.3 grams of Mg}{2 moles of HCl}$

mass of Mg= 0.729 grams

But 0.729 grams of Mg are not available, 0.0350 grams are available. Since you have less mass than you need to react with 0.06 moles of HCl, Mg will be the limiting reagent.

7 0

3 years ago

A certain amount of H2S was added to a 2.0 L flask and allowed to come to equilibrium. At equilibrium, 0.072 mol of H2 was found

SIZIF [17.4K]

Answer:

0.098 moles H₂S

Explanation:

The reaction that takes place is

2H₂(g) + S₂(g) ⇄ 2H₂S(g) keq = 7.5

We can express the equilibrium constant as:

keq = [H₂S]² / [S₂] [H₂]² = 7.5

With the volume we can calculate the equilibrium concentration of H₂:

[H₂] = 0.072 mol / 2.0 L = 0.036 M

The stoichiometric ratio tells us that the concentration of S₂ is half of the concentration of H₂:

[S₂] = [H₂] / 2 = 0.036 M / 2 = 0.018 M

Now we can calculate [H₂S]:

7.5 = [H₂S]² / (0.018*0.036²)

[H₂S] = 0.013 M

So 0.013 M is the concentration of H₂S at equilibrium.

This would amount to (0.013 M * 2.0 L) 0.026 moles of H₂S

The moles of H₂ at equilibrium are equal to the moles of H₂S that reacted.

Initial moles of H₂S - Moles of H₂S that reacted into H₂ = Moles of H₂S at equilibrium

Initial moles of H₂S - 0.072 mol = 0.026 mol

Initial moles of H₂S = 0.098 moles H₂S

8 0

3 years ago

the density of gold is 19.3 g/cm3. a 3.4 mg piece of gold is hammered into a square that is 8.6 x 10-6 cm thick. what is the len

faltersainse [42]

Answer:

The length of a side of the square is 4.53 cm

Explanation:

Volume (V) = mass/density

mass = 3.4 mg = 3.4/1000 = 0.0034 g

density = 19.3 g/cm^3

V = 0.0034/19.3 = 1.76×10^-4 cm^3

Volume = area × thickness

Area = volume/thickness = 1.76×10^-4/8.6×10^-6 = 20.48 cm^2

Length of one side of the square = sqrt(area of square) = sqrt(20.48 cm^2) = 4.53 cm

3 0

3 years ago

What are the three particles of an atom

g100num [7]

The three particles of any atom are
electron) the smallest particle and is held in shells around the nucleus of the atom
proton) is found in the nucleus and is much larger than an electron
neutron) the same mass as a proton and also found in the nucleus of the atom

5 0

3 years ago

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