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Fantom [35]
3 years ago
5

An unknown solution has an H+ concentration of 10-12 moles per liter. Which of the following statements correctly describes this

solution? The solution is basic in nature./ The solution is acidic in nature. /The solution is neutral in nature.
Chemistry
2 answers:
melisa1 [442]3 years ago
5 0

Answer:

The pH of the solution 12 which means that solution is basic in nature.

Explanation:

The pH of the solution is defined as negative logarithm of hydrogen ions concentration in a solution. Mathematically written as:

pH=-\log[H^+]

Given concentration of hydrogen ions= [H^+]=10^{-12} M

pH=-log[10^{-12}]=12

  • Solution with pH less than 7 are considered as acidic as solutions.
  • Solution with pH more than 7 are considered as basic as solutions.

The pH of the solution 12 which means that solution is basic in nature.

11Alexandr11 [23.1K]3 years ago
3 0
Given the concentration of H+, we can calculate the pH through the formula pH= -log(H+). In this problem, the pH is 12. Hence the solution is basic in nature. 
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Inertia increases as an object's_______increases.
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Answer:

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Explanation:

Inertia increases as an object's <u>Mass</u> increases.

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3 years ago
When an electron in an atom spontaneously jumps from a higher energy state to a lower energy state, the atom?
vlabodo [156]
If an atom suffers from a collision, that causes an electron to jump from a lower to higher state, it is called collisional excitation 
6 0
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A piece of metal with a mass of 611 g is placed into a graduated cylinder that contains 25.1 ml of water, raising the water leve
jeka94

Mass of metal piece is 611 g and volume of graduated cylinder is 25.1 mL. When metal piece is placed in the graduated cylinder water level increases to 56.7 mL. The increase in volume is due to volume of metal piece that gets added to the volume of water.

Thus, volume of metal piece can be calculated by subtracting initial volume from the final one.

V_{metal}=V_{final}-V_{initial}=(56.7-25.1)mL=31.6 mL

Thus, volume of metal piece will be 31.6 mL. The mass of metal piece is given 611 g, density of metal can be calculated as follows:

d=\frac{m}{V}=\frac{611 g}{31.6 mL}=19.33 g/mL

Therefore, density of metal is 19.33 g/mL.

3 0
3 years ago
How much energy is required to raise the temperature of 3 kg of iron from 20° C to 25°C? Use the table below and this equation:
ElenaW [278]

The energy required to raise the temperature of 3 kg of iron from 20° C to 25°C is 6,750 J( Option B)

<u>Explanation:</u>

Given:

Specific Heat capacity of Iron= 0.450 J/ g °C

To Find:

Required Energy to raise the Temperature

Formula:

Amount of energy required is given by the formula,

Q = mC (ΔT)

Solution:

M = mass of the iron in g

So 3 kg = 3000 g

C = specific heat of iron = 0.450 J/ g °C [ from the given table]

ΔT = change in temperature = 25° C - 20°C = 5°C

Plugin the values, we will get,

Q = 3000 g ×  0.450 J/ g °C ×  5°C

 = 6,750 J

So the energy required is 6,750 J.

7 0
3 years ago
Read 2 more answers
The compound 1-iodododecane is a nonvolatile liquid with a density of 1.20g/ml. the density of mercury is 13.6g/ml. part a what
valina [46]

As the atmospheric pressure is, P = dgh

Here d is the density of the mercury,

g is gravitation = 9.8 m/s²

h is height of the column, P = 751 torr = (751 torr × 1 atm / 760 torr) (101325 Pa) (1 N/m² / 1 Pa) = 100125 N/m²

Where, 1 N = 1 Kg / ms²

Thus, P = 100125 Kg / m³. s²

Therefore, height of the mercury column, when the atmospheric pressure is 751 torr,

h = P / gd

= (100125 kg / m³. s²) / (9.8 m/s²) (13.6 × 10³ kg / m³) = 0.751 m

As, d₁h₁ = d₂h₂

Here, d₁ is the density of the non-volatile liquid = 1.20 g/ml

d₂ is the density of the mercury = 13.6 g/ml

h₂ = 0.751 m

Thus, putting the values we get,

h₁ = d₂h₂ /d₁ = 13.6 g/ml × 0.751 m / 1.20 g/ml

= 8.5 m


3 0
3 years ago
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