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vichka [17]
4 years ago
15

Two campers dock a canoe. One camper has a mass of 100.0 kg and moves forward at 3.0 m/s as he leaves the canoe to step onto the

dock. With what speed do the canoe and other camper move if their combined mass is 175.0 kg
Physics
1 answer:
Solnce55 [7]4 years ago
4 0

Answer:

The combined speed of camper and canoe is 1.71 m/s.

Explanation:

Given that,

Mass of camper 1, m = 100 kg

Speed of camper 1, v = 3 m/s

The combined mass of another camper and canoe is, M = 175 kg

We need to find the combined speed of camper and canoe. According to the conservation of linear momentum, the momentum of first camper is equal to linear momentum of the canoe and the second camper.

mv=MV\\\\V=\dfrac{mv}{M}\\\\V=\dfrac{100\times 3}{175}\\\\V=1.71\ m/s

So, the combined speed of camper and canoe is 1.71 m/s.

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Alex_Xolod [135]

The expression for the magnitude of the electric field between two uniform conducting plates is

E=\frac{V}{d}

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As the potential 6.00 cm from the zero volt plate (and 4.00 cm from the other) is 420 V.

Therefore,

E = \frac{420 \ V}{6 \times 10^{-2} m } = 70 \times 10^2 \ V/m

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3 years ago
Two iron bolts of equal Mass one at a hundred see another at 55 Sierra place in the insulated cylinder assuming the heat capacit
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Answer:

T_2 = 77.5c

Explanation:

From the question we are told that

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Temp of 2nd bolt T_2=55

Generally the equation showing the relationship between  heat & temperature is given by

  q=cm \triangle T

Generally heat released  by the iron bolt  = heat gained by the iron bolt

Generally solving mathematically

     -(0.45*m* (T_2-100  \textdegree c)) = 0.45*m*(T_2 -55\textdegree c)

     -(T_2-100 \textdegree c)) = (T_2 -55 \textdegree c)

      T_2 +T_2= 100 \textdegree c+55 \textdegree c

      T_2=\frac{155 \textdegree c}{2}

      T_2 = 77.5 \textdegree c

Therefore T_2 = 77.5 \textdegree c is the final temperature inside the container

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Answer:

14 m/s

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