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valentinak56 [21]
3 years ago
14

0.12M NaOH solution to neutralize Oxalic acid solution. you will need the molecular weight of the Oxalic acid

Chemistry
1 answer:
wel3 years ago
6 0

Answer:

2 NaOH (aq) + H2C2O4(aq) Na2C2O4(aq) + 2H2O (l) Moles of NaOH used = Molarity x Volume (L) = 0.12 mole/L x 0.025

Explanation:

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Find the percent composition of C7H5N3O6
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Finding percent composition is fairly easy. You only need to divide the mass of an element by the total mass of the compound. We can do this one element at a time.

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Add all of those pieces together.

84.077 + 5.04 + 42.021 + 95.994 = 227.132 g/mol is your total. Since we also just found the mass of each individual element, the next step will be very easy.

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You can check your work by making sure they add up to 100%. The ones I just found add up to 99.99, which is close enough. A small difference (no more than 0.03 in my experience) is just a matter of where you rounded your numbers.

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