1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
creativ13 [48]
3 years ago
12

Specify the number of possible isomers of bromodimethylbenzene. 6 Write the name of one of these isomers. Abbreviate ortho (o),

meta (m) and para (p), no italics, if you elect to use these terms.fill in the blank 2 Specify the number of possible isomers of aromatic compounds with the formula C7H8O. ___ Write the name of one of these isomers. Abbreviate ortho (o), meta (m) and para (p), no italics, if you elect to use these terms. fill in the blank 4
Chemistry
1 answer:
cupoosta [38]3 years ago
5 0

Answer:

Explanation:

See  attached file .

You might be interested in
What is the maximum number of covalent
Lera25 [3.4K]

Answer:

D. 4

Explanation:

Answer and Explanation: Carbon can form a maximum of four covalent bonds. Carbon can share up to four pairs of electrons, therefore, the carbon atom fills its outer energy level and achieves chemical stability.

4 0
3 years ago
Hospital patients are administered oxygen from an pressurized
Nataly_w [17]

Answer:

110L

Explanation:

Boyle's Law states that P1×V1=P2×V2

Volume is indirectly proportional to Pressure so P×V is constant

P1=55atm

V1=6L

P2=3atm

V2 is to be found

P1×V1=P2×V2

6×55=3×V2

330=3×V2

Answer: V2=110L

8 0
3 years ago
Choose all the answers that apply.
Anni [7]

Answer:

I believe it's the lowest portion of the atmosphere

3 0
3 years ago
Calculate the mass percent composition of carbon in C4F8
Anon25 [30]
My work to your question

4 0
4 years ago
How many grams of NaOH needed to completely neutralize 3L of 1.75M HCL
Sedaia [141]

Answer:

209.98 g of NaOH

Explanation:

We are given;

  • Volume of HCl as 3 L
  • Molarity of HCl as 1.75 M

We are required to calculate the mass of NaOH required to completely neutralize the acid given.

First, we write a  balanced equation for the reaction between NaOH and HCl

That is;

NaOH + HCl → NaCl + H₂O

Second, we determine the number of moles of HCl

Number of moles = Molarity × Volume

                             = 1.75 M × 3 L

                             = 5.25 moles

Third, we use the mole ratio to determine the moles of NaOH

From the reaction,

1 mole of NaOH reacts with 1 mole of HCl

Therefore;

Moles of NaOH = Moles of HCl

                          = 5.25 moles

Fourth, we determine the mass of NaOH

Molar mass of NaOH = 39.997 g/mol

Mass of NaOH = 5.25 moles × 39.997 g/mol

                        = 209.98 g

Thus, 209.98 g of NaOH will completely neutralize 3L of 1.74 M HCl

6 0
3 years ago
Other questions:
  • As we move from left to right across the periodic table, what is the general trend? A) Atomic radii increase. B) Electronegaviti
    8·2 answers
  • Explain why two liters of hydrogen gas and one liter of oxygen gas react to form two liters of water, when the pressures and tem
    14·1 answer
  • In the reaction K2CrO4(aq) + PbCl2(aq) → 2KCl(aq) + PbCrO4(s), how many grams of PbCrO4 will precipitate out from the reaction b
    10·2 answers
  • A 25.00 mL solution of 0.150 M NaCl is combined with 10.00 mL of a 0.0750 M CaCl2 solution. Assuming a total volume of 35.00 mL,
    7·1 answer
  • What is the empirical formula of a compound composed of 3.25% hydrogen ( H ), 19.36% carbon ( C ), and 77.39% oxygen ( O ) by ma
    6·1 answer
  • Find the natural abundance of Si-30.
    12·1 answer
  • Which combination best represent the mass and charge of a neutron?
    9·1 answer
  • Suppose you had 2.0158 grams of hydrogen (H2).
    9·1 answer
  • 12. The molar mass of water is 18.0
    15·1 answer
  • Nitrogen gas can be prepared by passing gaseous ammonia over solid copper (II) oxide at high temperatures. If 18.1 g of Nh3 is r
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!