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2 years ago

How do inertia and centripetal force combine to keep an object moving in circular motion?

Physics

2 answers:

tigry1 [53]2 years ago

8 0

Answer:

Centripetal force acts toward the center of the circle, and inertia keeps the object moving forward.

Explanation:

Inertia is a property of a body by virtue of its mass due to which a body tends to resist any change in its current state of motion.

A body in a circular motion tends to move forward due to inertia but centripetal fore which acts towards the center changes its direction and the body moves along the circumference of the circle. The combination of centripetal force and inertia keeps the object in the circular motion.

Aleonysh [2.5K]2 years ago

7 0

<span>Centripetal force acts toward the center of the circle, and inertia keeps the object moving forward.
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You can carry a 50 N weight up a flight of stairs that is 3 m high in 10 s. Then you carry 40 N up two flights of stairs in 20 s

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You can do 50 and 10 and carry the 30 and it would be in the same power so you’ll have the same energy

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2 years ago

En un balde de 25 cm de altura se hace un orificio a 15 cm del suelo.calcula la velocidad de salida del agua

Contact [7]

Explanation:

En un balde de 25 cm de altura se hace un orificio a 15 cm del suelo.calcula la velocidad de salida del agua

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2 years ago

A force F=0.12N is aplied on spring and spring elongates by 3cm . specific constant of spring

PilotLPTM [1.2K]

The spring constant is 4 N/m

Explanation:

When a spring is stretched/compressed by the application of a force, the relationship between the magnitude of the force applied and the elongation of the spring is given by Hooke's law:

$F=kx$

where

F is the magnitude of the spring applied

k is the spring constant

x is the elongation of the spring, relative to its equilibrium position

For the spring in this problem, we have:

F = 0.12 N (force applied)

x = 3 cm = 0.03 m (elongation of the spring)

Therefore, we can solve the formula for k to find the spring constant:

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3 years ago

A plastic film moves over two drums. During a 4-s interval the speed of the tape is increased uniformly from v0 = 2ft/s to v1 =

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Answer:

Question 1)

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This is the linear acceleration of the drums. Since the tape does not slip on the drums, by the rule of rolling without slipping,

$v = \omega R\\a = \alpha R$

where α is the angular acceleration.

In order to continue this question, the radius of the drums should be given.

Let us denote the radius of the drums as R, the angular acceleration of drum B is

α = 0.5/R.

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Question 2)

a) In a rocket propulsion question, the acceleration of the rocket can be found by the following formula:

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3 years ago