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Marta_Voda [28]
3 years ago
7

Elena (60.0 kg) and Madison (65.0 kg) are ice-skating at the Rockefeller ice rink in New Yok city. Their friend Tanner sees Elen

a move to the right with a speed of 1.20 m/s towards Madison. Madison is moving to the left at a speed of 2.50 m/s towards Elena.
1. What is Elena's momentum? (Assume the positive direction is to the right and the negative direction is to the left.)
2, What is Madison's momentum? (Assume the positive direction is to the right and the negative direction is to the left.)
3. What is the total momentum of Elena and Madison?
4. When Elena and Madison collide, they hold onto each other. With what speed and in what direction do both of them move at?
Physics
1 answer:
Bas_tet [7]3 years ago
8 0

1. +72.0 kg m/s

The momentum of an object is given by:

p = mv

where

m is the mass of the object

v is its velocity

Taking "to the right" as positive direction, for Elena we have

m = 60.0 kg is the mass

v = +1.20 m/s is the velocity

So, Elena's momentum is

p_e=(60.0 kg)(+1.20 m/s)=+72.0 kg m/s

2. -162.5 kg m/s

Here Madison is moving in the opposite direction of Elena (to the left), so her velocity is

v = -2.50 m/s

while her mass is

m = 65.0 kg

Therefore, her momentum is

p_m= (65.0 kg)(-2.50 m/s)=-162.5 kg m/s

3. -90.5 kg m/s

The total momentum of Elena and Madison is equal to the algebraic sum of their momenta; taking into account the correct signs, we have:

p=p_e + p_m = +72.0 kg m/s - 162.5 kg m/s =-90.5 kg m/s

4. 0.72 m/s to the left

We can find the final speed of Elena and Madison by using the law of conservation of momentum. In fact, the final momentum must be equal to the initial momentum (before the collision).

The initial momentum is the one calculated at the previous step:

p_i = -90.5 kg m/s

while the final momentum (after the collision) is given by

p_f = (m_e + m_m) v

where

m_e is Elena's mass

m_m is Madison's mass

v is their final velocity

According to the law of conservation of momentum,

p_i = p_f\\p_i = (m_e + m_m) v

So we can find v:

v=\frac{p_i}{m_e + m_m}=\frac{-90.5 kg m/s}{60.0 kg+65.0 kg}=-0.72 m/s

and the direction is to the left, since the sign is negative.

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The coefficient of static friction is 0.222

Explanation:

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\mu is the coefficient of static friction

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In this problem, we have:

r = 564 m

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g=9.8 m/s^2

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\mu = \frac{v^2}{gr}=\frac{35^2}{(9.8)(564)}=0.222

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What speed would a proton need to achieve in order to circle Earth 1790 km above the magnetic equator, where the Earth's mag- ne
irinina [24]

Answer:

The velocity is 31.25 m/s and direction is toward west.

Explanation:

Given that,

Distance h= 1790 km = 1.790\times10^{6}\ m

Magnetic field B=4\times10^{-8}\ T

Mass of proton m=1.673\times10^{-21}\ Kg

Radius of earth R =6.38\times10^{6}\ m

Radius of orbit r=R+h

r=6.38\times10^{6}+1.790\times10^{6}

r=8170000\ m

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Using formula of magnetic field

Bvq=\dfrac{mv^2}{r}

v=\dfrac{Bqr}{m}

Put the value into the formula

v=\dfrac{4\times10^{-8}\times1.6\times10^{-19}\times8170000}{1.673\times10^{-21}}

v=31.25\ m/s

Hence, The velocity is 31.25 m/s and direction is toward west.

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tino4ka555 [31]

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Explanation:

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