1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Katarina [22]
3 years ago
10

Two cars having different weights are traveling on a level surface at different constant velocities. Within the same time interv

al, greater force will always be required to stop a car that has the greater
a)weight
b)velocity
c)kinetic energy
d)momentum
Physics
1 answer:
GuDViN [60]3 years ago
4 0

I think you're saying that once you start pushing on the cars, you want to be able to stop each one in the same time. 

This is sneaky.  At first, I thought it must be both 'c' and 'd'.  But it's not
kinetic energy, for reasons I'm not ambitious enough to go into.
(And besides, there's no great honor awarded around here for explaining
why any given choice is NOT the answer.)

The answer is momentum.

Momentum is (mass x speed).  Change in momentum is (force x time).

No matter the weight (mass) or speed of the car, the one with the greater
momentum is always the one that will require the greater (force x time)
to stop it.  If the time is the same for any car, then more momentum
will always require more force.


You might be interested in
A. 36 mins 52.5 secs<br> b. 24mins 22.5 secs<br> c. 13 mins 0 secs<br> d. 9 mins 45 secs
DedPeter [7]
I think it might be A. I’m sorry if I’m wrong
5 0
3 years ago
Read 2 more answers
an egg (0.05 kg) hits the ground at a speed of 10 m/s and cracks . what was the momentum of the egg when it hit?
Anastaziya [24]
The momentum should be .5 because you multiply the mass and velocity to get momentum
6 0
3 years ago
A billiard ball is moving in the x-direction at 30.0 cm/s and strikes another billiard ball moving in the y-direction at 40.0 cm
PSYCHO15rus [73]

Explanation:

Given that,

Initial speed of the billiard ball 1, u = 30i cm/s

Initial speed of another billiard ball 2, u' = 40j cm/s

After the collision,

Final speed of first ball, v = 50 cm/s

Final speed of second ball, v' = 0 (as it stops)

Let us consider that both balls have same mass i.e. m

Initial kinetic energy of the system is :

K_i=\dfrac{1}{2}mu^2+\dfrac{1}{2}mu'^2\\\\K_i=\dfrac{1}{2}m(u^2+u'^2)\\\\K_i=\dfrac{1}{2}m((30)^2+(40)^2)\\\\K_i=1250m\ J

Final kinetic energy of the system is :

K_f=\dfrac{1}{2}mv^2+\dfrac{1}{2}mv'^2\\\\K_f=\dfrac{1}{2}m(v^2+v'^2)\\\\K_f=\dfrac{1}{2}m((50)^2+(0)^2)\\\\K_f=1250m\ J

The change in kinetic energy of the system is equal to the difference of final and initial kinetic energy as :

\Delta K=K_f-K_i\\\\\Delta K=1250m-1250m\\\\\Delta K=0

So, the change in kinetic energy of the system as a result of the collision is equal to 0.    

7 0
4 years ago
What is the critical angle for the interface between water and light flint? nflint= 1.58, nwater=1.33?
Angelina_Jolie [31]
When light crosses the interface between a medium with higher refractive index and a medium with lower refractive index, there is a maximum value of the angle of incidence after which there is no refraction, but all the light is reflected, and this maximum value is called critical angle.

The critical angle is given by
\theta_C = \arcsin ( \frac{n_2}{n_1} )
where n1 is the refractive index of the first medium while n2 is the refractive index of the second medium. In our problem, n1=1.33 and n2=1.58, so the critical angle is
\theta_C = \arcsin ( \frac{1.33}{1.58} )=57.3 ^{\circ}

3 0
3 years ago
What is the energy in joules of a mole of photons associated with visible light of wavelength 486 nm?
Marrrta [24]

Answer:

2.46\cdot 10^5 J

Explanation:

The enegy of a single photon is given by:

E=\frac{hc}{\lambda}

where

h is the Planck costant

c is the speed of light

\lambda is the wavelength of the photon

In this problem,

\lambda=486 nm=4.86\cdot 10^{-7}m

so the energy of one photon is

E_1=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{4.86\cdot 10^{-7}m}=4.09\cdot 10^{-19} J

1 mole of photons contains a number of Avogadro of photons:

N_A = 6.022\cdot 10^{23}

therefore, the total energy of 1 mole of these photons will be

E=N_A E_1 = (6.022\cdot 10^{23})(4.09\cdot 10^{-19} J)=2.46\cdot 10^5 J

3 0
4 years ago
Other questions:
  • A ball is dropped from rest from the top of a cliff that is 15.0 m high. From ground level, a second ball is thrown straight upw
    8·1 answer
  • is it possible for the gravitational force between two 50-kg objects to be less than the gravitational force between a 59-kg obj
    13·1 answer
  • [25 points] Imagine two billiard balls on a pool table. Ball A has a mass of 7 kilograms and ball B has a mass of 2 kilograms. T
    9·1 answer
  • What are the two thing change when an object is in motion
    11·1 answer
  • What is the main difference between conglomerate and breccia?
    10·1 answer
  • What is a phone message?
    15·2 answers
  • How much work (in J) is required to expand the volume of a pump from 0.0 L to 2.7 L against an external pressure of 1.0 atm?
    7·1 answer
  • Are colavent bonds more likely to be found in compounds contaning both materals and nonmetals or compounds contaning only nonmet
    10·2 answers
  • A line _____ on a typical Speed vs. Time graph means an object is experiencing a constant acceleration.
    10·2 answers
  • Summarize the weather conditions related to a warm front. Remember to include all data collected on warm fronts in this activity
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!