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docker41 [41]
3 years ago
5

What is the velocity of an object that has a momentum of 4,000 kg-m/s and a mass of 115 kg? Round to the nearest hundredth.

Physics
1 answer:
iren [92.7K]3 years ago
6 0

Answer:

B. 34.78 m/s

Explanation:

Momentum of a body or an object is given as the product of its velocity and its mass.

Therefore;

Momentum= velocity x mass

But; velocity = ? mass =115 kg , momentum = 4,000 kgm/s

Thus; velocity= momentum/mass

                      = 4,000/115

                       = 34.78 m/s

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A piece of wood has a mass of 8g and a volume of 10cm³ work out the density of the wood
olchik [2.2K]

Answer:

<h2>0.8 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 8 g

volume = 10 cm³

We have

density =   \frac{8}{10}   =  \frac{4}{5}  = 0.8 \\

We have the final answer as

<h3>0.8 g/cm³</h3>

Hope this helps you

5 0
3 years ago
EXPERTS/ACE and people that wanna help 4 sure only!
mario62 [17]
That first one you have selected (3,-3) works in both equations so it's correct.
good job.

you can do this guess and test method with multiple choice answers. If it works in both equations it is the solution. Otherwise use substitution or elimination to combine the two into one equation in only one variable. Then you can solve for the one variable first and use it to solve for the other.

3 0
3 years ago
A 7450 kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.35 m/s2 and feels no appreci
bagirrra123 [75]

Answer:

a) 520m

b) 10.30 s

c) 100,95 m/s

Explanation:

a) According the given information, the rocket suddenly stops when it reach the height of 520m, because the engines fail, and then it begins the free fall.

This means the maximum height this rocket reached before falling  was 520 m.

b) As we are dealing with constant acceleration (due gravity) g=9.8 \frac{m}{s^{2}} we can use the following formula:

y=y_{o}+V_{o} t-\frac{gt^{2}}{2}   (1)

Where:

y_{o}=520 m  is the initial height of the rocket (at the exact moment in which it stops due engines fail)

y=0  is the final height of the rocket (when it finally hits the launch pad)

V_{o}=0 is the initial velocity of the rocket (at the exact moment in which it stops the velocity is zero and then it begins to fall)

g=9.8m/s^{2}  is the acceleration due gravity

t is the time it takes to the rocket to hit the launch pad

Clearing t:

0=520 m+0-\frac{9.8m/s^{2} t^{2}}{2}   (2)

t^{2}=\frac{-520 m}{-4.9 m/s^{2}}   (3)

t=\sqrt{106.12 s^{2}   (4)

t=10.30 s   (5)  This is the time

c) Now we need to find the final velocity V_{f} for this rocket, and the following equation will be perfect to find it:

V_{f}=V_{o}-gt  (6)

V_{f}=0-(9.8 m/s^{2})(10.30 s)  (7)

V_{f}=-100.95 m/s  (8) This is the final velocity of the rocket. Note the negative sign indicates its direction is downwards (to the launch pad)

7 0
3 years ago
Carlos conduce su automóvil a 70 Km/h, mientras que Luis maneja una camioneta a la misma velocidad
DIA [1.3K]

Answer:

shsissjsisjuai

Explanation:

abajxyxaiaodkxfk

4 0
3 years ago
Why is it so important to know how the parts of a can opener work
Dafna1 [17]

Answer:

Hi there!

There are many possible answers!

My best guesses are:

1) Knowing how they work will prevent injury! For example, knowing that the gears twist will stop you from putting your finger in it!

2) Allowing you to use it! Knowing how to line up the edge of the can with the tool will let you use it properly!

Hope this helps

3 0
3 years ago
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