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nirvana33 [79]
2 years ago
9

A 100.0-kg bakery sign hangs from two thin cables as shown.

Physics
1 answer:
harina [27]2 years ago
5 0

Answer:

1. T₁ = 500 N

2. T₂ = 866 N

Explanation:

Please see attached photo for the diagram.

Thus, we can obtain obtained the value of T₁ and T₂ as follow:

1. Determination of T₁

Angle θ = 30

Hypothenus = 100 kg

Opposite = T₁ =?

Sine θ = Opposite /Hypothenus

Sine 30 = T₁ / 100

Cross multiply

T₁ = 100 × Sine 30

T₁ = 100 × 0.5

T₁ = 50 Kg

Multiply by 10 to express in Newton

T₁ = 50 × 10

T₁ = 500 N

2. Determination of T₂

Angle θ = 60

Hypothenus = 100 kg

Opposite = T₂ = ?

Sine θ = Opposite /Hypothenus

Sine 60 = T₂ / 100

Cross multiply

T₂ = 100 × Sine 60

T₂ = 100 × 0.8660

T₂ = 86.6 Kg

Multiply by 10 to express in Newton

T₂ = 86.6 × 10

T₂ = 866 N

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a 1020-hertz sound wave travels at 340 m/s in air with a wavelength of a) 30 m. b) 3 m. c) 0.333 m. d) 1 m. e) none of the above
eimsori [14]

The wavelength of the sound wave is equal to 0.333 m. Therefore, option (c) is correct.

<h3>What are frequency and wavelength?</h3>

The frequency of the wave can be defined as the number of oscillations that occur in one second and can be expressed in hertz. The wavelength can be defined as the distance between the two adjacent points of a wave such as two crests or troughs.

The relationship between frequency (ν), speed of sound waves (V), and  wavelength (λ):

V = νλ

Given, the frequency of the sound wave, ν = 10 Hz

The speed of the sound wave,V = 340 m/s

The wavelength of the sound waves can determine as follows

λ = V/ν = 340/1020 = 0.333 m.

Therefore, the wavelength of the sound wave is 0.333 m

Learn more about wavelength and frequency, here:

brainly.com/question/18651058

#SPJ1

5 0
10 months ago
An electron moving with a velocity v⃗ = 5.0 × 107 m/s i^ enters a region of space where perpendicular electric and a magnetic fi
stiv31 [10]

Answer:

Magnetic field, B=2\times 10^{-4}\ T

Explanation:

Given that,

Velocity of electron, v=5\times 10^7\ m/s

It enters  a region of space where perpendicular electric and a magnetic fields are present.

Magnitude of electric field, E=10^4\ V/m

We need to find the magnetic field will allow the electron to go through the region without being deflected.

Magnetic force on the electron, F_m=qvB\ sin\theta.......(1)

Electric force on the electron, F = q E........(2)

From equation (1) and (2) we get:

qvB\ sin\theta=qE

B=\dfrac{E}{v}

B=\dfrac{10^4\ V/m}{5\times 10^7\ m/s}

B = 0.0002 T

or

B=2\times 10^{-4}\ T

Hence, this is the required solution.

3 0
2 years ago
If you accelerate from rest at 12m/s^2 for 5 seconds, what is your finally velocity?
jeka94

Answer:

v=60m/s

Explanation:

Use the Kinematic Equation:

v=v_o+at

Plug in what is given and solve

v=0+(12)(5)

v=60m/s

3 0
2 years ago
In a carnival booth, you can win a stuffed giraffe if you toss a quarter into a small dish. the dish is on a shelf above the poi
Georgia [21]

components of the speed of the coin is given as

v_x = v cos60

v_x = 6.4 cos60 = 3.2 m/s

v_y = vsin60

v_y = 6.4 sin60 = 5.54 m/s

now the time taken by the coin to reach the plate is given by

t = \frac{\delta x}{v_x}

t = \frac{2.1}{3.2}

t = 0.656 s

now in order to find the height

h = vy * t + \frac{1}{2} at^2

h = 5.54 * 0.656 - \frac{1}{2}*9.8*(0.656)^2

h = 1.52 m

so it is placed at 1.52 m height

3 0
3 years ago
Is this right at all
Alja [10]
It is correct! good job :)
7 0
3 years ago
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